Submission #473922

#TimeUsernameProblemLanguageResultExecution timeMemory
473922SaraMostafaEuklid (COCI20_euklid)C++14
35 / 110
1082 ms312 KiB
#include <bits/stdc++.h> #include<unordered_map> using namespace std; #define ll long long #define endl "\n" #define Sara ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL); const long long mod=1e9+7; const double PI=acos(-1); // 1 2 3 --> 1,2,3 ...1,2..1,3..1..2,3..2..3..none (2 power number of elements) //1 2 3 --> 2--> 1,2..1,3..2,3..(!n/(r!(n-r)!)) aka:ncr // 1 2 3 -->2-->1,2..2,1..1,3..3,1..2,3..3,2..(n!/(n-r)!) aka:npr //1 2 3--> 1..1,2..1,2,3..2..2,3..3 number of subarrays -->(n*(n+1))/2 "sum of numbers from 1 to n." /* ll power(ll x,ll y) { if(y==0) return 1; else if(y==1) return x%mod; ll r=power(x%mod,((y%mod)/2)%mod); if(y%2==0) return ((r%mod)*(r%mod)); else return ((r%mod)*(r%mod)*(x%mod)); } ll inverse(ll md,ll x) { return power(x%mod,mod-2); } */ ll r(ll a,ll b) { while(a>1 && b>1) { if(a<b) swap(a,b); a/=b; } if(a==1) return b; else return a; } int main() { //freopen("input.in","r",stdin); Sara int t; cin>>t; while(t--) { ll h,g; cin>>g>>h; ll ans1=-1,ans2=-1; for(int i=1; i<=10000; i++) { ll a=g*i; for(int j=i; j<=10000; j++) { ll b=g*j; if(__gcd(a,b)==g && r(a,b)==h) { ans1=a; ans2=b; break; } } if(ans1!=-1) break; } cout<<ans1<<' '<<ans2<<endl; } return 0; }
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