Submission #473349

#TimeUsernameProblemLanguageResultExecution timeMemory
473349_L__Doktor (COCI17_doktor)C++17
40 / 100
439 ms32064 KiB
// This code is written by _L__ #include <bits/stdc++.h> using namespace std; #define endl '\n' #define F_word ios_base::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL); typedef long long ll; typedef long double ld; const int mod = 1e9+7, N = 2e5+13, inf = 1e9+1; const ld E = 1e-6; #define ff first #define ss second int main(void){ F_word; int n; cin >> n; int pref[n+1] = {}; int a[n+2] = {}, doc[n+4] = {}; for(int i = 1; i <= n; ++i){cin >> a[i]; doc[a[i]] = a[i]-i; pref[i]+=pref[i-1]; pref[i]+=(doc[a[i]]==0);}a[0] = 1; if(n <= 500){ int sum = 0, ans1 = 1, ans2 = 1; for(int i = 1; i <= n; ++i){ for(int j = i; j <= n; ++j){ reverse(a+i, a+j+1); ll x = 0; for(int k = 1; k <= n; ++k) x += (a[k] == k); if(x >= sum){ ans1 = i, ans2 = j, sum = x; } reverse(a+i, a+j+1); } } cout << a[ans1] << ' ' << a[ans2] << endl; return 0; } map<int, int> freq_odd, freq_even; for(int i = 1; i <= n; ++i) if(!(doc[a[i]]%2)) freq_odd[(i+a[i])/2]++; for(int i = 1; i <= n; ++i) if(doc[a[i]]%2) freq_even[(i+a[i])/2]++; ll ans_odd = 0, tar = 0, ans_even = 0; for(auto u: freq_odd) if(u.ss >= tar) {tar = u.ss, ans_odd = u.ff;} tar = 0; for(auto u: freq_even) if(u.ss >= tar) {tar = u.ss, ans_even = u.ff;} ll a_1 = ans_odd, a_2 = ans_odd, sum = 0, i = ans_odd-1, j = ans_odd+1, total = (a[a_1] == a_1); while(i > 0 && j <= n){ ll c = (a[i]+i)/2; if(c == ans_odd) ++total; c = (j+a[j])/2; if(c == ans_odd) ++total; ll x = total+pref[i-1]-pref[0]+pref[n]-pref[j]; if(x >= sum){ a_1 = i, a_2 = j, sum = x; } ++j; --i; } ll a_3 = ans_even, a_4 = ans_even+1, sum1 = 0; if(a_3 == 0 || a_4 == 0){a_3 = 0, a_4 = 0;} i = a_3-1, j = a_4+1, total = (a[a_3] == a_4)+(a[a_4] == a_3); while(i > 0 && j <= n){ ll c = (a[i]+i)/2; if(c == ans_even) ++total; c = (a[j]+j)/2; if(c == ans_even) ++total; ll x = total+pref[i-1]+pref[n]-pref[j]; if(x >= sum1){ a_3 = i, a_2 = j, sum1 = x; } ++j; --i; } if(sum >= sum1) cout << a[a_1] << ' ' << a[a_2] << endl; else cout << a[a_3] << ' ' << a[a_4] << endl; }
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