This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// This code is written by _L__
#include <bits/stdc++.h>
using namespace std;
#define endl '\n'
#define F_word ios_base::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL);
typedef long long ll;
typedef long double ld;
const ll mod = 1e9+7, N = 2e5+13, inf = 1e9+1;
const ld E = 1e-6;
#define ff first
#define ss second
int main(void){
F_word;
ll n; cin >> n;
ll a[n+2] = {}, doc[n+4] = {}; for(ll i = 1; i <= n; ++i){cin >> a[i]; doc[a[i]] = a[i]-i;}a[0] = 1;
map<ll, ll> freq_odd, freq_even;
for(ll i = 1; i <= n; ++i)
if(!(doc[a[i]]%2))
freq_odd[i+(doc[a[i]]/2)]++;
for(ll i = 1; i <= n; ++i)
if(doc[a[i]]%2){
freq_even[(a[i]+i)/2]++;
}
ll ans_odd = 0, tar = 0, ans_even = 0;
for(auto u: freq_odd)
if(u.ss >= tar)
{tar = u.ss, ans_odd = u.ff;}
tar = 0;
for(auto u: freq_even)
if(u.ss >= tar)
{tar = u.ss, ans_even = u.ff;}
if(ans_even == 0 && ans_odd == 0)return cout << 1 << ' ' << 1 << endl, 0;
if(ans_even == 0){
ll a_1 = ans_odd, a_2 = ans_odd, sum = 0, i = ans_odd, j = ans_odd;
while(i > 0 && j <= n){
reverse(a+i, a+j+1); ll x = 0;
for(ll k = 1; k <= n; ++k) x += (a[k] == k);
if(x >= sum){
a_1 = i, a_2 = j; sum = x;
}
reverse(a+i, a+j+1); ++j, --i;
}
cout << a[a_1] << ' ' << a[a_2] << endl;
} else if(ans_odd == 0){
ll a_3 = ans_even, a_4 = ans_even+1, sum1 = 0, i = a_3, j = a_4;
while(i > 0 && j <= n){
reverse(a+i, a+j+1); ll x = 0;
for(ll k = 1; k <= n; ++k) x += (a[k] == k);
if(x >= sum1){
a_3 = i, a_4 = j; sum1 = x;
}
reverse(a+i, a+j+1); ++j, --i;
}
cout << a[a_3] << ' ' << a[a_4] << endl;
} else {
//cout << ans_odd << ' ' << ans_even << endl;
ll a_1 = ans_odd, a_2 = ans_odd, sum = 0, i = ans_odd, j = ans_odd;
while(i > 0 && j <= n){
reverse(a+i, a+j+1); ll x = 0;
for(ll k = 1; k <= n; ++k) x += (a[k] == k);
if(x >= sum){
a_1 = i, a_2 = j; sum = x;
}
reverse(a+i, a+j+1); ++j, --i;
}
ll a_3 = ans_even, a_4 = ans_even+1, sum1 = 0; i = a_3, j = a_4;
while(i > 0 && j <= n){
reverse(a+i, a+j+1); ll x = 0;
for(ll k = 1; k <= n; ++k) x += (a[k] == k);
if(x >= sum1){
a_3 = i, a_4 = j; sum1 = x;
}
reverse(a+i, a+j+1); ++j, --i;
}
//cout << sum << ' ' << sum1 << endl;
if(sum >= sum1) cout << a[a_1] << ' ' << a[a_2] << endl;
else cout << a[a_3] << ' ' << a[a_4] << endl;
}
}
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