Submission #473254

#TimeUsernameProblemLanguageResultExecution timeMemory
473254_L__Doktor (COCI17_doktor)C++14
50 / 100
1094 ms30524 KiB
// This code is written by _L__ #include <bits/stdc++.h> using namespace std; #define endl '\n' #define F_word ios_base::sync_with_stdio(false), cin.tie(NULL), cout.tie(NULL); typedef long long ll; typedef long double ld; const ll mod = 1e9+7, N = 2e5+13, inf = 1e9+1; const ld E = 1e-6; #define ff first #define ss second int main(void){ F_word; ll n; cin >> n; ll a[n+2] = {}, doc[n+4] = {}; for(ll i = 1; i <= n; ++i){cin >> a[i]; doc[a[i]] = a[i]-i;}a[0] = 1; map<ll, ll> freq_odd, freq_even; for(ll i = 1; i <= n; ++i) if(!(doc[a[i]]%2)) freq_odd[i+(doc[a[i]]/2)]++; for(ll i = 1; i <= n; ++i) if(doc[a[i]]%2) freq_even[i+(doc[a[i]]/2)-1]++; ll ans_odd = 0, tar = 0, ans_even = 0; for(auto u: freq_odd) if(u.ss >= tar) {tar = u.ss, ans_odd = u.ff;} tar = 0; for(auto u: freq_even) if(u.ss >= tar) {tar = u.ss, ans_even = u.ff;} if(ans_even == 0 && ans_odd == 0)return cout << 1 << ' ' << 1 << endl, 0; if(ans_even == 0){ ll a_1 = ans_odd, a_2 = ans_odd, sum = 0, i = ans_odd, j = ans_odd; while(i > 0 && j <= n){ reverse(a+i, a+j+1); ll x = 0; for(ll k = 1; k <= n; ++k) x += (a[k] == k); if(x >= sum){ a_1 = i, a_2 = j; sum = x; } reverse(a+i, a+j+1); ++j, --i; } cout << a[a_1] << ' ' << a[a_2] << endl; } else if(ans_odd == 0){ ll a_3 = ans_even, a_4 = ans_even+1, sum1 = 0, i = a_3, j = a_4; while(i > 0 && j <= n){ reverse(a+i, a+j+1); ll x = 0; for(ll k = 1; k <= n; ++k) x += (a[k] == k); if(x >= sum1){ a_3 = i, a_4 = j; sum1 = x; } reverse(a+i, a+j+1); ++j, --i; } cout << a[a_3] << ' ' << a[a_4] << endl; } else { ll a_1 = ans_odd, a_2 = ans_odd, sum = 0, i = ans_odd, j = ans_odd; while(i > 0 && j <= n){ reverse(a+i, a+j+1); ll x = 0; for(ll k = 1; k <= n; ++k) x += (a[k] == k); if(x >= sum){ a_1 = i, a_2 = j; sum = x; } reverse(a+i, a+j+1); ++j, --i; } ll a_3 = ans_even, a_4 = ans_even+1, sum1 = 0; i = a_3, j = a_4; while(i > 0 && j <= n){ reverse(a+i, a+j+1); ll x = 0; for(ll k = 1; k <= n; ++k) x += (a[k] == k); if(x >= sum1){ a_3 = i, a_4 = j; sum1 = x; } reverse(a+i, a+j+1); ++j, --i; } if(sum >= sum1) cout << a[a_1] << ' ' << a[a_2] << endl; else cout << a[a_3] << ' ' << a[a_4] << endl; } }
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