Submission #473227

#TimeUsernameProblemLanguageResultExecution timeMemory
473227SaraMostafaGaraža (COCI17_garaza)C++14
0 / 160
4090 ms1100 KiB
#include <bits/stdc++.h> #include<unordered_map> using namespace std; #define ll long long #define endl "\n" #define Sara ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL); const long long mod=1e9+7; const double PI=acos(-1); // 1 2 3 --> 1,2,3 ...1,2..1,3..1..2,3..2..3..none (2 power number of elements) //1 2 3 --> 2--> 1,2..1,3..2,3..(!n/(r!(n-r)!)) aka:ncr // 1 2 3 -->2-->1,2..2,1..1,3..3,1..2,3..3,2..(n!/(n-r)!) aka:npr //1 2 3--> 1..1,2..1,2,3..2..2,3..3 number of subarrays -->(n*(n+1))/2 "sum of numbers from 1 to n." /* ll power(ll x,ll y) { if(y==0) return 1; else if(y==1) return x%mod; ll r=power(x%mod,((y%mod)/2)%mod); if(y%2==0) return ((r%mod)*(r%mod)); else return ((r%mod)*(r%mod)*(x%mod)); } ll inverse(ll md,ll x) { return power(x%mod,mod-2); } */ int main() { //freopen("input.in","r",stdin); Sara int n,q; cin>>n>>q; vector<ll>v(n); for(int i=0; i<n; i++) { cin>>v[i]; } while(q--) { int o; cin>>o; if(o==1) { ll x,val; cin>>x>>val; x--; v[x]=val; } else { ll l,r; cin>>l>>r; l--; r--; ll cnt=0; for(int i=l; i<=r; i++) { ll gcd=v[i]; for(int j=i; j<=r; j++) { if(__gcd(v[j],gcd)>1) { gcd=__gcd(gcd,v[j]); cnt++; } else break; } } cout<<cnt<<endl; } } return 0; }
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