Submission #470170

#	Time	Username	Problem	Language	Result	Execution time	Memory
470170		radal	Watermelon (INOI20_watermelon)	C++14	0 / 100	2121 ms	538164 KiB

Main

#include <bits/stdc++.h>
#define rep(i,l,r) for (int i = l; i < r; i++)
#define pb push_back
#define debug(x) cerr << #x <<  " : " << x << endl;
using namespace std;

typedef long long ll;

const ll N = 1e5+20;
int b[N];
int n,k;
int vis[N],din[N],a[N];
vector<int> in[N],out[N];
bool dfs(int v){
    vis[v] = 1;
    for (int u : out[v]){
        if(vis[u] == 1) return 0;
        if (!vis[u] && !dfs(u)) return 0;
    }
    vis[v] = 2;
    return 1;
}
int main(){
    ios :: sync_with_stdio(0); cin.tie(0); cout.tie(0);
    cin >> n >> k;
    rep(i,1,n+1) cin >> b[i];
    if (b[n] != -1){
        cout << -1;
        return 0;
    }
    vector<int> ve[500];
    int sz = n,p = 1;
    rep(i,1,n+1)
        ve[1].pb(i);
    while (true){
        if (!sz) break;
        bool f = 1;
        rep(i,0,sz){
            f &= (b[ve[p][i]] == -1);
            if (b[ve[p][i]] != p){
                ve[p+1].pb(ve[p][i]);
                if (i != sz-1){
                    in[ve[p][i+1]].pb(ve[p][i]);
                    out[ve[p][i]].pb(ve[p][i+1]);
                }
            }
            else{
                in[ve[p][i]].pb(ve[p][i+1]);
                out[ve[p][i+1]].pb(ve[p][i]);
            }
        }
        if (f){
            rep(i,1,sz){
                in[ve[p][i]].pb(ve[p][i-1]);
                out[ve[p][i-1]].pb(ve[p][i]);
            }
            break;
        }
        p++;
        if ((int)ve[p].size() == sz){
            cout << -1;
            return 0;
        }
        sz = ve[p].size();
    }
    priority_queue<int> pq;
    rep(i,1,n+1){
        if (!vis[i]){
            if (!dfs(i)){
                cout << -1;
                return 0;
            }
        }
        din[i] = out[i].size();
        if (!din[i])
            pq.push(-i);
    }
    p = 1;
    while (!pq.empty()){
        int v = -pq.top();
        pq.pop();
        a[v] = p;
        for (int u : in[v]){
            din[u]--;
            if (!din[u]) pq.push(-u);
        }
        p++;
    }
    rep(i,1,n+1) cout << a[i] << ' ';
}

• Subtask 1: 0 / 7
• Subtask 2: 0 / 25
• Subtask 3: 0 / 31
• Subtask 4: 0 / 18
• Subtask 5: 0 / 19