Submission #465569

#	Time	Username	Problem	Language	Result	Execution time	Memory
465569		Sench2006	Exam (eJOI20_exam)	C++14	Compilation error	0 ms	0 KiB

exam

#include <bits/stdc++.h>
#include <unordered_map>
using namespace std;

#define ll long long
#define ar array

#define fastio ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);

// --------------- SOLUTION --------------- //

const int N = 1e5+5;
int n;
int a[N], b[N];
int t[4 * N];
int nm[N], pm[N];
int dp[5001][5001];

void pre() {
    stack<int> s;
    for (int i = 1; i <= n; ++i) {
        while (!s.empty() && a[s.top()] <= a[i])
            s.pop();
        if (s.empty())
            pm[i] = 0;
        else
            pm[i] = s.top();
        s.push(i);
    }
    while (!s.empty())
        s.pop();
    for (int i = n; i >= 1; --i) {
        while (!s.empty() && a[s.top()] <= a[i])
            s.pop();
        if (s.empty())
            nm[i] = n + 1;
        else
            nm[i] = s.top();
        s.push(i);
    }
}

int t[N * 4];
void ubd(int tl, int tr, int x, int y, int pos)
{
    if (tl == tr)
    {
        t[pos] = y;
        return;
    }
    int m = (tl + tr) / 2;
    if (x <= m)
        ubd(tl, m, x, y, pos * 2);
    else
        ubd(m + 1, tr, x, y, pos * 2 + 1);
    t[pos] = max(t[pos * 2], t[pos * 2 + 1]);
}
 
int qry(int tl, int tr, int l, int r, int pos)
{
    if (l > r)
        return 0;
    if (tl == l && tr == r)
        return t[pos];
    int m = (tl + tr) / 2;
    return max(qry(tl, m, l, min(m, r), pos * 2),
               qry(m + 1, tr, max(m + 1, l), r, pos * 2 + 1));
}
 
map <int, int> mp;
int segTreeSolve() {
    for (int i = 1; i <= n; ++i)
        mp[a[i]] = i;
 
    for (int i = 1; i <= n; ++i) {
        if (mp.find(b[i]) == mp.end())
            continue;
        int x = mp[b[i]];
        if (pm[x] < i && i < nm[x]) {
            ubd(1, n, x, qry(1, n, 1, x, 1) + 1, 1);
        }
    }
    return t[1];
}

int less5000() {
    int ans = 0;
    for (int i = 1; i <= n; ++i) {
        for (int j = 1; j <= n; ++j) {
            if (a[i] == b[j] && pm[i] < j && j < nm[i]) {
                dp[i][j + 1] = max(dp[i][j + 1], dp[i][j] + 1);
            }
            dp[i][j + 1] = max(dp[i][j + 1], dp[i][j]);
            dp[i + 1][j] = max(dp[i + 1][j], dp[i][j]);
        }
    }
    for (int i = 1; i <= n + 1; ++i)
        for (int j = 1; j <= n + 1; ++j)
            ans = max(ans, dp[i][j]);
    return ans;
}

// int p[N];
// int sameBs() {
//     for (int i = 1; i <= n; ++i) {
//         p[i] = p[i - 1];
//         if (a[i] == b[i])
//             ++p[i];
//     }
 
//     next_max[0] = 0;
//     for (int i = 1; i <= n; ++i) {
//         if (a[i] > b[i]) {
//             next_max[i] = i;
//         }
//         else {
//             next_max[i] = next_max[i - 1];
//         }
//     }
//     prev_max[n + 1] = n + 1;
//     for (int i = n; i >= 1; --i) {
//         if (a[i] > b[i]) {
//             prev_max[i] = i;
//         }
//         else {
//             prev_max[i] = prev_max[i + 1];
//         }
//     }
 
//     int ans = 0;
//     for (int i = 1; i <= n; ++i) {
//         if (a[i] <= b[i] && p[prev_max[i] - 1] - p[next_max[i]] > 0) {
//                 ++ans;
//         }
//     }
 
//     return ans;
// }

void solve() { 
    cin >> n;
    for (int i = 1; i <= n; ++i)
        cin >> a[i];
    for (int i = 1; i <= n; ++i)
        cin >> b[i];
 
    // bool ok = true;
    // for (int i = 1; i <= n; ++i)
    //     if (b[i] != b[1]) {
    //         ok = false;
    //         break;
    //     }
 
    // if (ok) {
    //     cout << sameBs() << "\n";
    //     return;
    // }
    pre();
    if (n <= 5000) {
        cout << less5000() << "\n";
        return;
    }
    cout << segTreeSolve() << "\n";
}

int main() {
    fastio;
    // fileio;
    int tests = 1;
    // cin >> tests;
    while (tests--) {
        solve();
    }

    return 0;
}

Compilation message (stderr)

exam.cpp:43:5: error: redefinition of 'int t [400020]'
   43 | int t[N * 4];
      |     ^
exam.cpp:15:5: note: 'int t [400020]' previously declared here
   15 | int t[4 * N];
      |     ^