This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
/*
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* # # # # # # # # # # # #
* # # ##### # # # # # # #
* ###### # # # # # # ## # # #
* # # # # # # # # ## ## # #
* # # ##### #### #### # # ####
*/
#include <bits/stdc++.h>
using namespace std;
#define lli long long int
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define pii pair <int, int>
#define X first
#define Y second
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define info() cerr << __PRETTY_FUNCTION__ << ": " << __LINE__ << endl
void abc() {cerr << endl;}
template <typename T, typename ...U> void abc(T a, U ...b) {
cerr << a << ' ', abc(b...);
}
template <typename T> void printv(T l, T r) {
while (l != r) cout << *l << " \n"[++l == r];
}
template <typename A, typename B> istream& operator >> (istream& o, pair<A, B> &a) {
return o >> a.X >> a.Y;
}
template <typename A, typename B> ostream& operator << (ostream& o, pair<A, B> a) {
return o << '(' << a.X << ", " << a.Y << ')';
}
template <typename T> ostream& operator << (ostream& o, vector<T> a) {
bool is = false;
for (T i : a) {o << (is ? ' ' : '{'), is = true, o << i;}
return o << '}';
}
template <typename T> struct vv : vector <vector <T>> {
vv(int n, int m, T v) : vector <vector <T>> (n, vector <T>(m, v)) {}
vv() {}
};
template <typename T> struct vvv : vector <vv <T>> {
vvv(int n, int m, int k, T v) : vector <vv <T>> (n, vv <T>(m, k, v)) {}
vvv() {}
};
#ifdef Doludu
#define test(args...) info(), abc("[" + string(#args) + "]", args)
#define owo void(0)
#else
#define test(args...) void(0)
#define owo ios::sync_with_stdio(false); cin.tie(0)
#endif
const int mod = 1e9 + 7, N = 200001, logN = 18, K = 1000;
int main () {
owo;
int n;
cin >> n;
vector <pii> a(n);
for (int i = 0; i < n; ++i) cin >> a[i];
lli ans = 0;
for (int i = 0; i < n; ++i) {
int mn1 = a[i].X, mn2 = a[i].Y;
ans = max(ans, 1ll * a[i].X * a[i].Y);
for (int j = i + 1; j < n; ++j) {
mn1 = min(mn1, a[j].X);
mn2 = min(mn2, a[j].Y);
ans = max(ans, 1ll * mn1 * mn2 * (j - i + 1));
}
}
cout << ans << endl;
}
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