Submission #460528

#	Time	Username	Problem	Language	Result	Execution time	Memory
460528		benson0402	Bajka (COCI20_bajka)	C++14	20 / 70	5 ms	204 KiB

bajka

#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("Ofast")

#include <bits/stdc++.h>
using namespace std;

using ll = long long;
using pii = pair<int, int>;
using pll = pair<ll, ll>;
#define F first
#define S second
#define ALL(x) x.begin(), x.end()
#define MEM(x) memset(x, 0, sizeof(x))
#define MEMS(x) memset(x, -1, sizeof(x))

#define eb emplace_back
#define ep emplace
#define mkp make_pair

const int INF = 0x3f3f3f3f;
const ll LINF = 0x3f3f3f3f3f3f3f3f;
/*------------------------------------------------------------------*/

const int N = 300 + 5;

int dp[N], dp2[N];

inline void solve() {
	int n, m; cin >> n >> m;
	string a, b; cin >> a >> b;
	for(int i = 0; i < m; ++i) {
		for(int j = 0; j < N; ++j) dp[j] = INF;
		for(int j = 0; j < n; ++j) {
			if(!i && a[j] == b[i]) dp[j] = 0;
			else if(i && dp2[j] != INF) {
				for(int k = 0; k < n; ++k) if(j != k && a[k] == b[i])
					dp[k] = min(dp[k], dp2[j] + abs(j - k));
			}
		}
		copy(dp, dp + N, dp2);
	}
	int ans = INF;
	for(int i = 0; i < n; ++i) 
		ans = min(ans, dp2[i]);
	cout << (ans == INF ? -1 : ans) << '\n';
}

int main() {
	cin.tie(0), ios::sync_with_stdio(0);
	solve();
}

• Subtask 1: 20 / 20
• Subtask 2: 0 / 50