This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "rect.h"
#include <bits/stdc++.h>
using namespace std;
const int N = 2550;
const int M = 222;
bool good[M][M][M];
int n, m;
vector<vector<int> > a;
vector<int> dx = {0, 1, 0, -1}, dy = {1, 0, -1, 0};
bool visited[N][N];
int mnx, mny, mxx, mxy, cnt = 0;
void dfs(int x, int y){
visited[x][y] = true;
cnt++;
mnx = min(mnx, x);
mny = min(mny, y);
mxx = max(mxx, x);
mxy = max(mxy, y);
for (int i = 0; i < 4; i++){
int X = x + dx[i], Y = y + dy[i];
if (X > 0 && X < n - 1 && Y > 0 && Y < m - 1 && !visited[X][Y] && a[X][Y] == 0) dfs(X, Y);
}
}
long long count_rectangles(vector<vector<int> > _a) {
a = _a;
n = a.size(), m = a[0].size();
if (n < 3 || m < 3) return 0;
if (n == 3) {
int ans = 0;
for (int l = 1; l < m - 1; l++) {
int mx = 0;
for (int r = l; r < m - 1; r++) {
mx = max(mx, a[1][r]);
if (a[1][r] >= min(a[0][r], a[2][r])) break;
if (mx < min(a[1][l - 1], a[1][r + 1])) ans++;
}
}
return ans;
}
if (n <= 200 && m <= 200) {
for (int i = 1; i < n - 1; i++) {
for (int x = 1; x < m - 1; x++) {
int mx = 0;
for (int y = x; y < m - 1; y++) {
mx = max(mx, a[i][y]);
if (mx < min(a[i][x - 1], a[i][y + 1])) {
//cout << i << ' ' << x << ' ' << y << endl;
good[i][x][y] = true;
}
}
}
}
int ans = 0;
for (int i = 1; i < n - 1; i++) {
for (int x = 1; x < m - 1; x++) {
for (int y = x; y < m - 1; y++) {
int j = i;
vector<int> v(m);
while (j < n - 1 && good[j][x][y]) {
int cnt = 0;
for (int k = x; k <= y; k++) {
v[k] = max(v[k], a[j][k]);
cnt += v[k] < min(a[i - 1][k], a[j + 1][k]);
}
if (cnt == y - x + 1) ans++;
j++;
}
}
}
}
return ans;
}
int ans = 0;
for (int i = 1; i < n - 1; i++){
for (int j = 1; j < m - 1; j++){
if (visited[i][j] || a[i][j] == 1) continue;
mnx = mny = 1e9, mxx = mxy = cnt = 0;
dfs(i, j);
if (cnt != (mxx - mnx + 1) * (mxy - mny + 1)) continue;
bool ok = true;
for (int k = mnx; k <= mxx; k++){
if (a[k][mny - 1] == 0 || a[k][mxy + 1] == 0) ok = false;
}
for (int k = mny; k <= mxy; k++){
if (a[mnx - 1][k] == 0 || a[mxx + 1][k] == 0) ok = false;
}
if (ok) ans++;
}
}
return ans;
}
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