Submission #447246

#TimeUsernameProblemLanguageResultExecution timeMemory
447246zaneyuHedgehog Daniyar and Algorithms (IZhO19_sortbooks)C++14
100 / 100
1201 ms120556 KiB
/*input 5 2 3 5 1 8 2 1 3 6 2 5 3 */ #include<bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; #pragma GCC optimize("unroll-loops,no-stack-protector") //order_of_key #of elements less than x // find_by_order kth element typedef long long int ll; #define ld long double #define pii pair<ll,ll> typedef tree<pii, null_type, less<pii>, rb_tree_tag, tree_order_statistics_node_update> indexed_set; #define f first #define s second #define pb push_back #define REP(i,n) for(ll i=0;i<n;i++) #define REP1(i,n) for(int i=1;i<=n;i++) #define FILL(n,x) memset(n,x,sizeof(n)) #define ALL(_a) _a.begin(),_a.end() #define sz(x) (int)x.size() const ll maxn=1e6+5; const ll maxlg=__lg(maxn)+2; const ll INF64=4e18; const int INF=0x3f3f3f3f; const ll MOD=INF64; const ld PI=acos(-1); const ld eps=1e-9; #define lowb(x) x&(-x) #define MNTO(x,y) x=min(x,(__typeof__(x))y) #define MXTO(x,y) x=max(x,(__typeof__(x))y) #define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end())))) #define GET_POS(c,x) (lower_bound(c.begin(),c.end(),x)-c.begin()) ll mult(ll a,ll b){ return (a*b)%MOD; } ll mypow(ll a,ll b){ if(b<=0) return 1; ll res=1LL; while(b){ if(b&1) res=mult(res,a); a=mult(a,a); b>>=1; } return res; } int bit[maxn],arr[maxn],ans[maxn]; vector<pair<pii,int>> qq[maxn]; void upd(int p,int x){ ++p; while(p<maxn){ MXTO(bit[p],x); p+=lowb(p); } } int query(int p){ ++p; int ans=0; while(p){ MXTO(ans,bit[p]); p-=lowb(p); } return ans; } int main(){ ios::sync_with_stdio(false),cin.tie(0); int n,q; cin>>n>>q; vector<int> v; vector<pii> inv; REP(i,n){ cin>>arr[i]; while(sz(v) and arr[v.back()]<=arr[i]) v.pop_back(); if(sz(v)) inv.pb({v.back(),i}); v.pb(i); } sort(ALL(inv)); REP(i,q){ int l,r,k; cin>>l>>r>>k; --l,--r; qq[l].pb({{r,k},i}); } for(int i=n-1;i>=0;i--){ while(sz(inv) and inv.back().f>=i){ int l=inv.back().f,r=inv.back().s; upd(r,arr[l]+arr[r]); inv.pop_back(); } for(auto x:qq[i]){ ans[x.s]=query(x.f.f)<=x.f.s; } } REP(i,q) cout<<ans[i]<<'\n'; }
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