Submission #445550

#TimeUsernameProblemLanguageResultExecution timeMemory
445550grtSpecijacija (COCI20_specijacija)C++17
20 / 110
4085 ms267164 KiB
#include <bits/stdc++.h> #define ST first #define ND second #define PB push_back //#define int long long using namespace std; using ll = long long; using pi = pair<int,int>; using vi = vector<int>; const int nax = 400 * 1000 + 10; int n, q, t; ll seq[nax]; vector<pair<ll, int>>T1[(1 << 19)]; vector<pair<ll, int>>T2[(1 << 19)]; int R; vi V[nax]; map<ll,int>sc; ll starting[nax]; void add(int a, int b, int x, int ti) { a += R; b += R; T1[a].PB({T1[a].back().ST + x, ti}); if(a != b) T1[b].PB({T1[b].back().ST + x, ti}); while((a>>1) != (b>>1)) { if((a&1)==0) T1[a^1].PB({T1[a^1].back().ST + x, ti}); if(b&1) T1[b^1].PB({T1[b^1].back().ST + x, ti}); a >>=1; b >>=1; } } void ustaw(int a, int b, ll x, int ti) { a += R; b += R; T2[a].PB({x, ti}); if(a != b) T2[b].PB({x, ti}); while((a>>1) != (b>>1)) { if((a&1)==0) T2[a ^1].PB({x, ti}); if(b&1) T2[b ^1].PB({x, ti}); a >>=1; b >>=1; } } ll askVal(int x) { x += R; pair<ll,int> w = T2[x].back(); while(x > 1) { x>>=1; if(w.ND > T2[x].back().ND) { w = T2[x].back(); } } return w.ST; } int ask(int x) { x += R; int w = T1[x].back().ST; while(x > 1) { x >>= 1; w += T1[x].back().ST; } return w; } pair<ll,int> g(vector<pair<ll,int>>&vec, int ti) { int low = 0, high = (int)vec.size() - 1, mid; while(low <= high) { mid = (low + high) >> 1; if(vec[mid].ND >= ti) { low = mid + 1; } else { high = mid - 1; } } return vec[low - 1]; } ll askVal2(int x, int ti) { x += R; pair<ll,int>w = g(T2[x], ti); while(x > 1) { x >>= 1; pair<ll,int>w2 = g(T2[x], ti); if(w2.ND < w.ND) { w = w2; } } return w.ST; } int ask2(int x, int ti) { x += R; int w = g(T1[x], ti).ST; while(x > 1) { x >>= 1; w += g(T1[x], ti).ST; } return w; } int f(int x) { int low = 1, high = n + 1, mid; while(low <= high) { mid = (low + high) >> 1; if(ask(mid) >= x) { high = mid - 1; } else { low = mid + 1; } } return high + 1; } int f2(int x, int ti) { int low = 1, high = n + 1, mid; while(low <= high) { mid = (low + high) >> 1; if(ask2(mid, ti) >= x) { high = mid - 1; } else { low = mid + 1; } } return high + 1; } ll ustal(ll x) { int low = 1, high = n + 1, mid; while(low <= high) { mid = (low + high) >> 1; if(starting[mid] <= x) { low = mid + 1; } else { high = mid - 1; } } low--; int k = x - starting[low] + 1; int dep = low; int pos = f2(k, dep); return askVal2(pos, dep); } int par[2*nax][19], dp[2*nax]; ll inv[2 * nax]; void dfs(int x) { for(int nbh : V[x]) { dp[nbh] = dp[x] + 1; dfs(nbh); par[nbh][0] = x; } } int lca(int a, int b) { if(dp[a] < dp[b]) swap(a, b); for(int i = 18; i >= 0; --i) { if(dp[par[a][i]] >= dp[b]) { a = par[a][i]; } } if(a == b) return -a; for(int i = 18; i >= 0; --i) { if(par[a][i] != par[b][i]) { a = par[a][i]; b = par[b][i]; } } return par[a][0]; } __int32_t main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> n >> q >> t; ll start = 1; for(int i = 1; i <= n; ++i) { starting[i] = start; cin >> seq[i]; sc[seq[i]]; start += i; } starting[n + 1] = start; R = 1; while(R <= n + 1) R *= 2; for(int i = 1; i < 2 * R; ++i) { T1[i].PB({0, n + 2}); T2[i].PB({0, n + 2}); } for(int i = 1; i <= n + 1; ++i) { add(i, i, i, n + 1); ustaw(i, i, start + i - 1, n + 1); sc[start + i - 1]; } int nr = 1; for(auto &it : sc) { inv[nr] = it.ST; it.ND = nr++; } for(int i = n; i >= 1; --i) { // val = a[i] + i - start + 1 int val = seq[i] + i - start + 1; int pos = f(val + 1); int l = f(val), r = f(val + 2) - 1; ll val1 = askVal(l); ll val2 = askVal(r); V[sc[seq[i]]].PB(sc[val1]); V[sc[seq[i]]].PB(sc[val2]); ustaw(l, r, seq[i], i); add(pos, n + 1, -1, i); start -= i; } ll ans = 0; dp[1] = 1; dfs(sc[1]); for(int s = 1; s <= 18; ++s) { for(int i = 1; i <= nr; ++i) { par[i][s] = par[par[i][s - 1]][s - 1]; } } while(q--) { ll x, y; cin >> x >> y; x = ((x - 1 + t * ans)%((ll)(n+1)*(n+2)/2)) + 1; y = ((y - 1 + t * ans)%((ll)(n+1)*(n+2)/2)) + 1; ll xa = ustal(x); ll ya = ustal(y); //cout << xa << " " << ya << "\n"; if(xa == ya) { cout << min(x, y) << "\n"; ans = min(x, y); continue; } int l = lca(sc[xa], sc[ya]); if(l < 0) { cout << min(x, y) << "\n"; ans = min(x, y); continue; } cout << inv[l] << "\n"; ans = inv[l]; } }
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