oj.uz

답안 #445535

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
445535 2021-07-18T15:10:29 Z grt Specijacija (COCI20_specijacija) C++17
0 / 110
 4000 ms 250772 KB 
#include <bits/stdc++.h>
#define ST first
#define ND second
#define PB push_back

using namespace std;
using ll = long long;
using pi = pair<int,int>;
using vi = vector<int>;

const int nax = 200 * 1000 + 10;
int n, q, t;
ll seq[nax];

vector<pair<ll, int>>T1[(1 << 19)];
vector<pair<ll, int>>T2[(1 << 19)];
int R;
vi V[nax];
map<ll,int>sc;
ll starting[nax];

void add(int a, int b, int x, int ti) {
	a += R; b += R;
	T1[a].PB({T1[a].back().ST + x, ti});
	if(a != b) T1[b].PB({T1[b].back().ST + x, ti});
	while(a / 2 != b / 2) {
		if(a % 2 == 0) T1[a + 1].PB({T1[a + 1].back().ST + x, ti});
		if(b % 2 == 1) T1[b - 1].PB({T1[b - 1].back().ST + x, ti});
		a /= 2;
		b /= 2;
	}
}

void ustaw(int a, int b, ll x, int ti) {
	a += R; b += R;
	T2[a].PB({x, ti});
	if(a != b) T2[b].PB({x, ti});
	while(a / 2 != b / 2) {
		if(a % 2 == 0) T2[a + 1].PB({x, ti});
		if(b % 2 == 1) T2[b - 1].PB({x, ti});
		a /= 2;
		b /= 2;
	}
}

ll askVal(int x) {
	x += R;
	pair<ll,int> w = T2[x].back();
	while(x > 1) {
		x /= 2;
		if(w.ND > T2[x].back().ND) {
			w = T2[x].back();
		}
	}
	return w.ST;
}

int ask(int x) {
	x += R;
	int w = T1[x].back().ST;
	while(x > 1) {
		x /= 2;
		w += T1[x].back().ST;
	}
	return w;
}

pair<ll,int> g(vector<pair<ll,int>>&vec, int ti) {
	int low = 0, high = (int)vec.size() - 1, mid;
	while(low <= high) {
		mid = (low + high) / 2;
		if(vec[mid].ND >= ti) {
			low = mid + 1;
		} else {
			high = mid - 1;
		}
	}
	return vec[low - 1];
}

ll askVal2(int x, int ti) {
	x += R;
	pair<ll,int>w = g(T2[x], ti);
	while(x > 1) {
		x /= 2;
		pair<ll,int>w2 = g(T2[x], ti);
		if(w2.ND < w.ND) {
			w = w2;
		}
	}
	return w.ST;
}

int ask2(int x, int ti) {
	x += R;
	int w = g(T1[x], ti).ST;
	while(x > 1) {
		x /= 2;
		w += g(T1[x], ti).ST;
	}
	return w;
}

int f(int x) {
	int low = 1, high = n + 1, mid;
	while(low <= high) {
		mid = (low + high) / 2;
		if(ask(mid) >= x) {
			high = mid - 1;
		} else {
			low = mid + 1;
		}
	}
	return high + 1;
}

int f2(int x, int ti) {
	int low = 1, high = n + 1, mid;
	while(low <= high) {
		mid = (low + high) / 2;
		if(ask2(mid, ti) >= x) {
			high = mid - 1;
		} else {
			low = mid + 1;
		}
	}
	return high + 1;
}

ll ustal(ll x) {
	int low = 1, high = n + 1, mid;
	while(low <= high) {
		mid = (low + high) / 2;
		if(starting[mid] <= x) {
			low = mid + 1;
		} else {
			high = mid - 1;
		}
	}
	low--;
	int k = x - starting[low] + 1;
	int dep = low;
	int pos = f2(k, dep);
	return askVal2(pos, dep);
}

int par[2*nax][19], dp[2*nax];
ll inv[2 * nax];

void dfs(int x) {
	for(int nbh : V[x]) {
		dp[nbh] = dp[x] + 1;
		dfs(nbh);
		par[nbh][0] = x;
	}
}

int lca(int a, int b) {
	if(dp[a] < dp[b]) swap(a, b);
	for(int i = 18; i >= 0; --i) {
		if(dp[par[a][i]] >= dp[b]) {
			a = par[a][i];
		}
	}
	if(a == b) return a;
	for(int i = 18; i >= 0; --i) {
		if(par[a][i] != par[b][i]) {
			a = par[a][i];
			b = par[b][i];
		}
	}
	return par[a][0];
}


int main() {
	ios_base::sync_with_stdio(0);
	cin.tie(0);
	cin >> n >> q >> t;
	ll start = 1;
	for(int i = 1; i <= n; ++i) {
		starting[i] = start;
		cin >> seq[i];
		sc[seq[i]];
		start += i;
	}
	starting[n + 1] = start;
	R = 1;
	while(R <= n + 1) R *= 2;
	for(int i = 1; i < 2 * R; ++i) {
		T1[i].PB({0, n + 2});
		T2[i].PB({0, n + 2});
	}
	for(int i = 1; i <= n + 1; ++i) {
		add(i, i, i, n + 1);
		ustaw(i, i, start + i - 1, n + 1);
		sc[start + i - 1];
	}
	int nr = 1;
	for(auto &it : sc) {
		inv[nr] = it.ST;
		it.ND = nr++;
	}
	for(int i = n; i >= 1; --i) {
		// val = a[i] + i - start + 1
		int val = seq[i] + i - start + 1;
		int pos = f(val + 1);
		int l = f(val), r = f(val + 2) - 1;
		int val1 = askVal(l);
		int val2 = askVal(r);
		V[sc[seq[i]]].PB(sc[val1]);
		V[sc[seq[i]]].PB(sc[val2]);
		ustaw(l, r, seq[i], i);
		add(pos, n + 1, -1, i);
		start -= i;
	}
	ll ans = 0;
	dp[1] = 1;
	dfs(sc[1]);
	for(int s = 1; s <= 18; ++s) {
		for(int i = 1; i <= nr; ++i) {
			par[i][s] = par[par[i][s - 1]][s - 1];
		}
	}
	while(q--) {
		ll x, y;
		cin >> x >> y;
		x = ((x - 1 + t * ans)%((ll)(n+1)*(n+2)/2)) + 1;
		y = ((y - 1 + t * ans)%((ll)(n+1)*(n+2)/2)) + 1;
		ll xa = ustal(x);
		ll ya = ustal(y);
		//cout << xa << " " << ya << "\n";
		if(xa == ya) {
			cout << min(x, y) << "\n";
			ans = min(x, y);
			continue;
		}
		int l = lca(sc[xa], sc[ya]);
		cout << inv[l] << "\n";
		ans = inv[l];
	}
	
	
}

Subtask #1
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 2641 ms 249360 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #2
0 / 10.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 2641 ms 249360 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #3
0 / 30.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 2641 ms 249360 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #4
0 / 60.0

# 결과 실행 시간 메모리 Grader output
1 Execution timed out 4099 ms 250772 KB Time limit exceeded
2 Halted 0 ms 0 KB -