Submission #444688

#TimeUsernameProblemLanguageResultExecution timeMemory
444688NaimSSK blocks (IZhO14_blocks)C++14
53 / 100
128 ms175564 KiB
#include <bits/stdc++.h> #define ld long double #define endl "\n" #define fastio ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0); #define pb push_back #define mp(a,b) make_pair(a,b) #define ms(v,x) memset(v,x,sizeof(v)) #define all(v) v.begin(),v.end() #define ff first #define ss second #define rep(i, a, b) for(int i = a; i < (b); ++i) #define per(i, a, b) for(int i = b-1; i>=a ; i--) #define trav(a, x) for(auto& a : x) #define allin(a , x) for(auto a : x) #define Unique(v) sort(all(v));v.erase(unique(all(v)),v.end()); #define sz(v) ((int)v.size()) using namespace std; typedef vector<int> vi; #define y1 abacaba //#define left oooooopss #define db(x) cerr << #x <<" == "<<x << endl; #define db2(x,y) cerr<<#x <<" == "<<x<<", "<<#y<<" == "<<y<<endl; #define db3(x,y,z) cerr << #x<<" == "<<x<<", "<<#y<<" == "<<y<<", "<<#z<<" == "<<z<<endl; typedef long long ll; typedef pair<int,int> pii; typedef pair<ll,ll> pll; std::mt19937 rng((int) std::chrono::steady_clock::now().time_since_epoch().count()); ll cdiv(ll a, ll b) { return a/b+((a^b)>0&&a%b); } // divide a by b rounded up ll fdiv(ll a, ll b) { return a/b-((a^b)<0&&a%b); } // divide a by b rounded down //inline ll mod(ll n, ll m ){ ll ret = n%m; if(ret < 0) ret += m; return ret; } ll gcd(ll a, ll b){return (b == 0LL ? a : gcd(b, a%b));} ll exp(ll b,ll e,ll m){ b%=m; ll ans = 1; for (; e; b = b * b % m, e /= 2) if (e & 1) ans = ans * b % m; return ans; } // debug: void dbg_out() { cerr << endl; } template<typename Head, typename... Tail> void dbg_out(Head H, Tail... T){ cerr << ' ' << H; dbg_out(T...); } #ifdef LOCAL #define dbg(...) cerr<<"(" << #__VA_ARGS__<<"):" , dbg_out(__VA_ARGS__) , cerr << endl #else #define dbg(...) #endif // const int N = 8080; ll A[N],B[N]; ll dp[100100][110]; int32_t main(){ fastio; int n,k; cin >> n >> k; rep(i,0,100100)rep(j,0,110)dp[i][j] = 1e18; ll mx=0; rep(i,1,n+1){ cin >> A[i]; B[i] = A[i]; mx=max(mx,A[i]); dp[i][1] = mx; } sort(B+1,B+1+n,greater<ll>()); rep(i,2,k+1){ stack<pll> st; rep(j,1,n+1){ ll val = dp[j-1][i-1]; while(!st.empty() && st.top().ff < A[j]){ val=min(val,st.top().ss); st.pop(); } if(st.empty() || st.top().ff + st.top().ss > A[j] + val){ st.push(pll(A[j],val)); } if(j>=i) dp[j][i] = st.top().ff + st.top().ss; } } cout << dp[n][k] << endl; // math -> gcd it all // Did u check N=1? Did you switch N,M? }
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