Submission #443031

#TimeUsernameProblemLanguageResultExecution timeMemory
443031leakedMarriage questions (IZhO14_marriage)C++14
96 / 100
1588 ms3152 KiB
#include <bits/stdc++.h>
//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("-O3")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#define vec vector
#define sz(x) ( int)x.size()
#define m_p make_pair
#define f first
#define s second
#define pb push_back
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(),x.rend()
using namespace std;
typedef long long ll;
typedef pair<ll, int> pli;
typedef pair<int,ll> pil;
typedef pair<int,int> pii;
typedef unsigned long long ull;
auto rng=bind(uniform_int_distribution<int>(1,1000),mt19937(time(0)));
template<class T> bool umax(T &a,const T &b){return (a<b?a=b,1:0);}
template<class T> bool umin(T &a,const T &b){return (a>b?a=b,1:0);}
const int N=3e4+1;
const int K=165;
const int M=2001;
vec<int> g[N+M];
int uk;
int mt[N+M];
int h[N+M],u[N+M],tt,n,m;
int tr;
bool kuhn(int v){
    if(u[v]==tt) return 0;
    u[v]=tt;
    for(auto &z : g[v]){
        if(h[z] && mt[z]==-1){
            mt[z]=v;mt[v]=z;
            return 1;
        }
    }
    for(auto &z : g[v]){
        if(h[z] && kuhn(mt[z])){
            mt[z]=v;mt[v]=z;
            return 1;
        }
    }
    return 0;
}
signed main(){
    ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
    int k;
    cin>>n>>m>>k;
    for(int i=0;i<k;i++){
        int v,u;
        cin>>v>>u;--v;--u;
        g[v].pb(u+n);
        g[u+n].pb(v);
    }
    fill(mt,mt+n+m,-1);
    for(int i=0;i<m;i++) h[i+n]=1;
    int r=-1;
    int c=0;
    ll ans=0;
    for(int l=0;l<n;l++){
        if(l){
            h[l-1]=0;
            if(mt[l-1]!=-1){
                tt++;
                mt[mt[l-1]]=-1;
                c--;c+=kuhn(mt[l-1]);
                mt[l-1]=-1;
            }
        }
        while(r<n && c!=m){
            r++;tt++;
            h[r]=1;c+=kuhn(r);
        }
        ans+=n-r;
//        cerr<<l<<' '<<r<<endl;
    }
    cout<<ans;
    return 0;
}

/*
5
1 2
2 3
3 4
4 5
5 1
*/
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