# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
443019 | leaked | Marriage questions (IZhO14_marriage) | C++14 | 27 ms | 1824 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
//#pragma GCC optimize("unroll-loops")
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("-O3")
//#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
#define vec vector
#define sz(x) ( int)x.size()
#define m_p make_pair
#define f first
#define s second
#define pb push_back
#define all(x) x.begin(),x.end()
#define rall(x) x.rbegin(),x.rend()
using namespace std;
typedef long long ll;
typedef pair<ll, int> pli;
typedef pair<int,ll> pil;
typedef pair<int,int> pii;
typedef unsigned long long ull;
auto rng=bind(uniform_int_distribution<int>(1,1000),mt19937(time(0)));
template<class T> bool umax(T &a,const T &b){return (a<b?a=b,1:0);}
template<class T> bool umin(T &a,const T &b){return (a>b?a=b,1:0);}
const int N=3e4+1;
const int K=165;
const int M=2001;
vec<int> g[N];
int mt[N];
int wh[N];
int u[N],tt,n,m;
int tl,tr;
bool kuhn(int v){
if(u[v]==tt) return 0;
u[v]=tt;
for(auto &z : g[v]){
if(z>=tl && z<=tr && mt[z]==-1){
mt[z]=v;
wh[v]=z;
return 1;
}
}
for(auto &z : g[v]){
if(z>=tl && z<=tr && kuhn(mt[z])){
mt[z]=v;
wh[v]=z;
return 1;
}
}
return 0;
}
int check(int l,int r){
tl=l;tr=r;
for(int i=0;i<m;i++){
if(wh[i]==-1) continue;
mt[wh[i]]=-1;
wh[i]=-1;
}
for(int i=0;i<m;i++){
tt++;
if(!kuhn(i)) return 0;
}
return 1;
}
signed main(){
ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
int k;
cin>>n>>m>>k;
for(int i=0;i<k;i++){
int v,u;
cin>>v>>u;--v;--u;
g[u].pb(v);
}
for(int i=0;i<N;i++){
mt[i]=-1;
wh[i]=-1;
}
int l=0,r=n;
while(l!=r){
int tm=(l+r)>>1;
if(check(tm,-1)) l=tm+1;
else r=tm;
}
l--;
r=n-1;
ll ans=0;
// cout<<check(1,4);
for(int i=l;i>=0;i--){
// cerr<<i<<' '<<r<<endl;
while(check(i,r-1)) r--;
// cout<<i<<' '<<r<<endl;
ans+=(n-r);
}
cout<<ans;
return 0;
}
/*
5
1 2
2 3
3 4
4 5
5 1
*/
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---|---|---|---|---|
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