Submission #442366

#TimeUsernameProblemLanguageResultExecution timeMemory
442366elazarkorenGame (eJOI20_game)C++17
20 / 100
1087 ms33040 KiB
#include <iostream> #include <vector> #include <algorithm> #define chkmin(a, b) a = min(a, b) #define chkmax(a, b) a = max(a, b) #define x first #define y second using namespace std; typedef vector<int> vi; typedef vector<vi> vvi; typedef vector<bool> vb; typedef vector<vb> vvb; typedef pair<int, int> pii; const int infinity = 1e9; vvb edges1, edges2; vvi id1, id2; int n, m; inline bool IsEdge1(int i, int j, int bit) { if (edges1[i][j]) return true; if (id1[i][j] != -1) return !((bit >> id1[i][j]) & 1); return false; } inline bool IsEdge2(int i, int j, int bit) { if (edges2[i][j]) return true; if (id2[i][j] != -1) return !((bit >> id2[i][j]) & 1); return false; } inline bool Inside(int i, int j, int bit) { if (i < 0 || i >= n || j < 0 || j >= m) return false; return IsEdge1(i, j, bit) && IsEdge1(i + 1, j, bit) && IsEdge2(i, j, bit) && IsEdge2(i, j + 1, bit); } int main() { cin >> n >> m; edges1.resize(n + 1, vb(m)), edges2.resize(n, vb(m + 1)); vector<pair<pii, bool>> edges; id1.resize(n + 1, vi(m, -1)), id2.resize(n, vi(m + 1, -1)); for (int i = 0; i <= n; i++) { for (int j = 0; j < m; j++) { char c; cin >> c; edges1[i][j] = c == '1'; if (c == '0') { id1[i][j] = edges.size(); edges.push_back({{i, j}, false}); } } } for (int i = 0; i < n; i++) { for (int j = 0; j <= m; j++) { char c; cin >> c; edges2[i][j] = c == '1'; if (c == '0') { id2[i][j] = edges.size(); edges.push_back({{i, j}, true}); } } } int sz = edges.size(); int pow = 1 << sz; vi dp1(pow, -infinity), dp2(pow, infinity); dp1[0] = dp2[0] = 0; for (int i = 1; i < pow; i++) { for (int j = 0; j < sz; j++) { if (!((i >> j) & 1)) continue; int squares = 0; int sub = i - (1 << j); if (edges[j].y) { squares = Inside(edges[j].x.x, edges[j].x.y, sub) + Inside(edges[j].x.x, edges[j].x.y - 1, sub); } else { squares = Inside(edges[j].x.x, edges[j].x.y, sub) + Inside(edges[j].x.x - 1, edges[j].x.y, sub); } chkmax(dp1[i], (squares ? dp1[sub] : dp2[sub]) + squares); chkmin(dp2[i], (squares ? dp2[sub] : dp1[sub]) - squares); } } cout << dp1[pow - 1]; }
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