Submission #442216

#	Time	Username	Problem	Language	Result	Execution time	Memory
442216		SorahISA	Dungeons Game (IOI21_dungeons)	C++17	37 / 100	440 ms	207800 KiB

dungeons

#include "dungeons.h"
#pragma GCC optimize("Ofast", "unroll-loops")
#include <bits/stdc++.h>
using namespace std;

#define int long long
// #define double long double
using pii = pair<int, int>;
template<typename T>
using Prior = std::priority_queue<T>;
template<typename T>
using prior = std::priority_queue<T, vector<T>, greater<T>>;

#define X first
#define Y second
#define eb emplace_back
#define pb pop_back
#define pf pop_front
#define ALL(x) begin(x), end(x)
#define RALL(x) rbegin(x), rend(x)

namespace {

mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());

const int maxn = 4E5 + 5;
const int lgmx = 19;

int N;
vector<int> S, P, W, L;

int anc[lgmx][maxn], max_val[lgmx][maxn], sum_str[lgmx][maxn];

} /// end of namespace

void init(int32_t _N, vector<int32_t> _S, vector<int32_t> _P, vector<int32_t> _W, vector<int32_t> _L) {
    N = _N;
    for (auto &x : _S) S.eb(x);
    for (auto &x : _P) P.eb(x);
    for (auto &x : _W) W.eb(x);
    for (auto &x : _L) L.eb(x);
    
    memset(anc, 0x00, sizeof(anc));
    memset(max_val, 0x00, sizeof(max_val));
    memset(sum_str, 0x00, sizeof(sum_str));
    
    for (int i = 0; i < N; ++i) {
        anc[0][i] = W[i];
        max_val[0][i] = S[i];
        sum_str[0][i] = S[i];
    }
    anc[0][N] = N;
    
    for (int lay = 1; lay < lgmx; ++lay) {
        for (int i = 0; i <= N; ++i) {
            int par = anc[lay-1][i];
            anc[lay][i] = anc[lay-1][par];
            max_val[lay][i] = max(max_val[lay-1][i], max_val[lay-1][par]);
            sum_str[lay][i] = sum_str[lay-1][i] + sum_str[lay-1][par];
        }
    }
}

int simulate(int32_t now, int32_t Z) {
    /// s[i] = p[i] ///
    while (now != N) {
        // cerr << "now: " << now << " " << Z << "\n";
        for (int lay = lgmx-1; lay >= 0 and now != N; --lay) {
            // cerr << lay << " " << now << " " << max_val[lay][now] << "\n";
            if (Z >= max_val[lay][now]) {
                Z += sum_str[lay][now];
                now = anc[lay][now];
            }
        }
        if (now == N) break;
        if (Z >= S[now]) Z += S[now], now = W[now];
        else             Z += P[now], now = L[now];
    }
    return Z;
}

• Subtask 1: 11 / 11
• Subtask 2: 26 / 26
• Subtask 3: 0 / 13
• Subtask 4: 0 / 12
• Subtask 5: 0 / 27
• Subtask 6: 0 / 11