Submission #441534

#TimeUsernameProblemLanguageResultExecution timeMemory
441534abc864197532Genetics (BOI18_genetics)C++17
46 / 100
381 ms1728 KiB
#include <bits/stdc++.h>
using namespace std;
#define lli long long int
#define X first
#define Y second
#define pb push_back
#define eb emplace_back
#define mp make_pair
#define pii pair<int, int>
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define test(args...) abc("[" + string(#args) + "]", args)
void abc() {cerr << endl;}
template <typename T, typename ...U> void abc(T a, U ...b) {
    cerr << a << ' ', abc(b...);
}
template <typename T> void printv(T l, T r) {
    while (l != r) cout << *l << " \n"[++l == r];
}
const int mod = 1e9 + 7, N = 200000;

bitset <1800> A[1800];

int main () {
    ios::sync_with_stdio(false);
    cin.tie(0);
    int n, m, k;
    cin >> n >> m >> k;
    if (n <= 100) {
        vector <string> s(n);
        for (int i = 0; i < n; ++i) cin >> s[i];
        for (int ans = 0; ans < n; ++ans) {
            bool is = true;
            for (int i = 0; i < n; ++i) if (ans != i) {
                    int cnt = k;
                    for (int j = 0; j < m; ++j) cnt -= s[i][j] != s[ans][j];
                    is &= !cnt;
                }
            if (is) return cout << ans + 1 << endl, 0;
        }
    } else {
        for (int i = 0; i < n; ++i) {
            string s;
            cin >> s;
            for (int j = 0; j < m; ++j) {
                if (s[j] == 'A') A[i][j].flip();
            }
        }
        for (int ans = 0; ans < n; ++ans) {
            bool is = true;
            for (int i = 0; i < n; ++i) if (ans != i) {
                    is &= (A[i] ^ A[ans]).count() == k;
                }
            if (is) return cout << ans + 1 << endl, 0;
        }
    }
}

Compilation message (stderr)

genetics.cpp: In function 'int main()':
genetics.cpp:52:51: warning: comparison of integer expressions of different signedness: 'std::size_t' {aka 'long unsigned int'} and 'int' [-Wsign-compare]
   52 |                     is &= (A[i] ^ A[ans]).count() == k;
      |                           ~~~~~~~~~~~~~~~~~~~~~~~~^~~~
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