# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
440788 | hibye1217 | Gap (APIO16_gap) | C++17 | 0 ms | 0 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// gap.h //
void MinMax(long long, long long, long long*, long long*);
// grader.cpp //
#include <stdio.h>
#include <stdlib.h>
// #include "gap.h"
static void my_assert(int k){ if (!k) exit(1); }
static int subtask_num, N;
static long long A[100001];
static long long call_count;
long long findGap(int, int);
void MinMax(long long s, long long t, long long *mn, long long *mx)
{
int lo = 1, hi = N, left = N+1, right = 0;
my_assert(s <= t && mn != NULL && mx != NULL);
while (lo <= hi){
int mid = (lo+hi)>>1;
if (A[mid] >= s) hi = mid - 1, left = mid;
else lo = mid + 1;
}
lo = 1, hi = N;
while (lo <= hi){
int mid = (lo+hi)>>1;
if (A[mid] <= t) lo = mid + 1, right = mid;
else hi = mid - 1;
}
if (left > right) *mn = *mx = -1;
else{
*mn = A[left];
*mx = A[right];
}
if (subtask_num == 1) call_count++;
else if (subtask_num == 2) call_count += right-left+2;
}
int main()
{
FILE *in = stdin, *out = stdout;
my_assert(2 == fscanf(in, "%d%d", &subtask_num, &N));
my_assert(1 <= subtask_num && subtask_num <= 2);
my_assert(2 <= N && N <= 100000);
for (int i=1;i<=N;i++) my_assert(1 == fscanf(in, "%lld", A+i));
for (int i=1;i<N;i++) my_assert(A[i] < A[i+1]);
fprintf(out, "%lld\n", findGap(subtask_num, N));
fprintf(out, "%lld\n", call_count);
}
#define NOTSUBMIT
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
/// gap.cpp ///
#ifndef NOTSUBMIT
#include "gap.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#endif
// Subtask 1 Only
ll arr[100020];
ll findGap(int T, int N){
if (T == 1){
ll mn = 0, mx = 1e18;
int st = 1, ed = N;
while (st <= ed){
MinMax(mn, mx, &arr[st], &arr[ed]);
mn = arr[st]+1; mx = arr[ed]-1;
st += 1; ed -= 1;
}
ll ans = 0;
for (int i = 1; i < N; i++){
ans = max(ans, arr[i+1] - arr[i]);
}
return ans;
}
}