Submission #435703

#	Time	Username	Problem	Language	Result	Execution time	Memory
435703		MladenP	Financial Report (JOI21_financial)	C++17	48 / 100	4050 ms	8696 KiB

Main

#include <bits/stdc++.h>
#define MAXN 300010
#define fi first
#define se second
#define pii pair<int,int>
#define pb push_back
#define INF 1000000000
#define mid (l+r)/2
#define PRINT(x) cerr<<#x<<'='<<x<<endl;
using namespace std;
int R[MAXN], A[MAXN], seg[4*MAXN], dp[MAXN];
vector<pii> v;
vector<int> buffer;
void update(int node, int l, int r, int idx, int val) {
    if(l == r) {
        seg[node] = val;
        return;
    }
    if(idx <= mid) update(2*node, l, mid, idx, val);
    else update(2*node+1, mid+1, r, idx, val);
    seg[node] = max(seg[2*node], seg[2*node+1]);
}
int query(int node, int l, int r, int L, int R) {
    if(L <= l && r <= R) return seg[node];
    int rez = 0;
    if(L <= mid) rez = max(rez, query(2*node, l, mid, L, R));
    if(R > mid) rez = max(rez, query(2*node+1, mid+1, r, L, R));
    return rez;
}
int main() {
    ios::sync_with_stdio(false); cin.tie(0);
    int N, D; cin >> N >> D;
    for(int i = 1; i <= N; i++) {
        cin >> A[i];
        v.pb({A[i], -i});
    }
    fill(seg, seg+4*MAXN, 0);
    sort(v.begin(), v.end());
    /*
    for(auto xx : v) {
        int idx = -xx.se;
        PRINT(idx);
        R[idx] = min(N, max(idx+D, query(1, 1, N, idx, min(N, idx+D))));
        update(1, 1, N, idx, R[idx]);
    }
    */
    ///DEBUG BRUTE
    for(int i = 1; i <= N; i++) {
        R[i] = min(N, i+D);
        for(int j = i+1; j <= min(N, R[i]); j++) {
            if(A[j] <= A[i]) R[i] = max(R[i], min(N, j+D));
        }
    }
    ///
    ///for(int i = 1; i <= N; i++) PRINT(R[i]);
    fill(seg, seg+4*MAXN, -INF);
    update(1, 1, N, N, 0);
    sort(v.rbegin(), v.rend());
    for(int i = 0; i < N; i++) {
        int idx = -v[i].se;
        dp[idx] = query(1, 1, N, idx, R[idx])+1;
        update(1, 1, N, idx, dp[idx]);
    }
    int rez = 0;
    for(int i = 1; i <= N; i++) {
        rez = max(rez, dp[i]);
    }
    cout << rez;
    return 0;
}

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 20 / 20
• Subtask 4: 0 / 12
• Subtask 5: 0 / 5
• Subtask 6: 0 / 35