Submission #435424

#TimeUsernameProblemLanguageResultExecution timeMemory
435424zaneyuTable Tennis (info1cup20_tabletennis)C++14
0 / 100
53 ms9116 KiB
/*input
4 2
1 2 3 4 5 6
*/
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> indexed_sett;
//order_of_key #of elements less than x
// find_by_order kth element
typedef long long int ll;
#define ld double
#define pii pair<ll,ll>
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define FILL(n,x) memsett(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (int)x.size()
const ll maxn=2e5+5;
const ll maxlg=__lg(maxn)+2;
const ll INF64=4e17;
const int INF=0x3f3f3f3f;
const ll MOD2=3006703054056749LL;
const ll MOD=1e9+7;
const ld PI=acos(-1);
const ld eps=1e-4;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
#define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
ll mult(ll a,ll b){
    return ((a%MOD)*(b%MOD))%MOD;
}
ll mypow(ll a,ll b){
    ll res=1;
    while(b){
        if(b&1) res=mult(res,a);
        a=mult(a,a);
        b/=2;
    }
    return res;
}
int arr[maxn];
int ar[maxn],l[maxn],r[maxn];
int32_t main(){
    ios::sync_with_stdio(false),cin.tie(0);
    int n,k;
    cin>>n>>k;
    REP(i,n+k) cin>>arr[i];
    map<int,vector<pii>> mp;
    REP(i,k){
        for(int j=n+k-1;j>=n+i-1;j--){
            mp[arr[i]+arr[j]].pb({i,j});
        }
    }
    vector<pii> vv;
    for(auto x:mp){
        if(sz(x.s)>=k){
            for(auto z:x.s) vv.pb(z);
        }
    }
    for(auto x:vv){
        int i=x.f,j=x.s;
        int pp=0,lp=0,rp=0;
        int s=arr[i]+arr[j],ans=0;
        for(int a=i;a<=j;a++){
            while(pp and ar[pp]+arr[a]>s) --pp;
            if(pp and ar[pp]+arr[a]==s) ++ans,l[lp++]=ar[pp],r[rp++]=arr[a];
            else if(a<=(i+j)/2) ar[++pp]=arr[a];
        }
        if(ans==(n/2)){
            REP(i,n/2) cout<<l[n/2-i-1]<<' ';
            REP(i,n/2) cout<<r[i]<<' ';
            return 0;
        }
        
    }
}
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