Submission #433548

#	Time	Username	Problem	Language	Result	Execution time	Memory
433548		misir	Palindromes (APIO14_palindrome)	C++14	73 / 100	1092 ms	23376 KiB

palindrome

#include <bits/stdc++.h>
using namespace std;
#define INF 1<<30
#define endl '\n'
#define maxn 100005
#define tc prllf("Case %d: ", cs)
#define tcn prllf("Case %d:\n", cs);
#define FASTIO ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0);
typedef long long ll;
const double PI = acos(-1.0);

#define dbg1(x) cerr << #x << " = " << x << endl;
#define dbg2(x, y) cerr << #x << " = " << x << ", " << #y << " = " << y << endl;
#define dbg3(x, y, z) cerr << #x << " = " << x << ", " << #y << " = " << y << ", " << #z << " = " << z << endl;
#define dbg4(w,x, y, z) cerr << #w << " = " << w << ", " <<#x << " = " << x << ", " << #y << " = " << y << ", " << #z << " = " << z << endl;

template < typename F, typename S >
ostream& operator << ( ostream& os, const pair< F, S > & p ) {
    return os << "(" << p.first << ", " << p.second << ")";
}

template < typename T >
ostream &operator << ( ostream & os, const vector< T > &v ) {
    os << "{";
    for (auto it = v.begin(); it != v.end(); ++it) {
        if ( it != v.begin() ) os << ", ";
        os << *it;
    }
    return os << "}";
}

template < typename T >
ostream &operator << ( ostream & os, const set< T > &v ) {
    os << "[";
    for (auto it = v.begin(); it != v.end(); ++it) {
        if ( it != v.begin()) os << ", ";
        os << *it;
    }
    return os << "]";
}

template < typename F, typename S >
ostream &operator << ( ostream & os, const map< F, S > &v ) {
    os << "[";
    for (auto it = v.begin(); it != v.end(); ++it) {
        if ( it != v.begin() ) os << ", ";
        os << it -> first << " = " << it -> second ;
    }
    return os << "]";
}

#define dbg(args...) do {cerr << #args << " : "; faltu(args); } while(0)

clock_t tStart = clock();
#define timeStamp dbg("Execution Time: ", (double)(clock() - tStart)/CLOCKS_PER_SEC)

void faltu () { cerr << endl; }

template <typename T>
void faltu( T a[], ll n ) {
    for (ll i = 0; i < n; ++i) cerr << a[i] << ' ';
    cerr << endl;
}

template <typename T, typename ... hello>
void faltu( T arg, const hello &... rest) { cerr << arg << ' '; faltu(rest...); }
// Program showing a policy-based data structure.
#include <ext/pb_ds/assoc_container.hpp> // Common file 
#include <ext/pb_ds/tree_policy.hpp>
#include <functional> // for less 
#include <iostream>
using namespace __gnu_pbds;
using namespace std;
// GNU link : https://goo.gl/WVDL6g
typedef tree<ll, null_type, less_equal<ll>, rb_tree_tag,
        tree_order_statistics_node_update>
        new_data_set;

/**___________________________________________________**/
const ll N = 100005;
ll idx, t;
ll link[N];
ll len[N];
ll tr[N][26];
string s;
ll occ[N];

void initTree()
{
    memset(tr, 0, sizeof tr);
    memset(link, 0, sizeof link);
    memset(len, 0, sizeof len);

    len[1] = -1;
    link[1] = 1;
    len[2] = 0;
    link[2] = 1;
    idx = 2;
    t = 2;
}

void addletter(ll pos)
{
    while (s[pos - len[t] - 1] != s[pos]) t = link[t];
    ll x = link[t];
    while (s[pos - len[x] - 1] != s[pos]) x = link[x];
    ll c = s[pos] - 'a';
    if (!tr[t][c]) {
        tr[t][c] = ++idx;
        len[idx] = len[t] + 2;
        link[idx] = len[idx] == 1 ? 2 : tr[x][c];
    }
    t = tr[t][c];
    occ[t]++;
}


//https://vjudge.net/problem/HDU-3948
int main()
{
    FASTIO
    /*
#ifndef ONLINE_JUDGE
    freopen("in.txt", "r", stdin);
    freopen("out.txt", "w", stdout);
    freopen("error.txt", "w", stderr);
#endif
    //*/
    ll T;
    // scanf("%d", &T);
    T = 1;
    for (ll cs = 1; cs <= T; cs++) {
        initTree();
        cin >> s;
        s = ' ' + s;
        ll n = s.size();
        for (ll i = 1; i < n; i++) {
            addletter(i);
        }
        // prllf("Case #%d: %d\n", cs, idx - 2);
    }

    // for (ll i = idx; i > 2; i--)
       
    ll ans = 0;
    for (ll i = idx; i > 2; i--) {
         occ[link[i]] += occ[i];
        ans = max(ans, len[i] * occ[i]);
    }
    cout << ans << "\n";
    return 0;
}

• Subtask 1: 8 / 8
• Subtask 2: 15 / 15
• Subtask 3: 24 / 24
• Subtask 4: 26 / 26
• Subtask 5: 0 / 27