Submission #433240

#	Time	Username	Problem	Language	Result	Execution time	Memory
433240		parsabahrami	Dabbeh (INOI20_dabbeh)	C++17	25 / 100	2105 ms	445032 KiB

Main

#include <bits/stdc++.h>
     
using namespace std;
     
typedef long long int ll;
typedef pair<int, int> pii;
  
#define SZ(x)                       (int) x.size()
#define F                           first
#define S                           second
     
const int N = 3e5 + 10, MOD[] = {(int) 1e9 + 9, (int) 1e9 + 7};
struct pair_hash {
    template <class T1, class T2>
    size_t operator () (const std::pair<T1,T2> &p) const {
        auto h1 = std::hash<T1>{}(p.first);
        auto h2 = std::hash<T2>{}(p.second);
        return h1 ^ h2;  
    }
};

int pw[2][N], H[2][N], dp[20][N], rmq[20][20][N], lg[N], n, m, q, base[] = {37, 31}; 
char S[N * 2]; 
unordered_map<pii, int, pair_hash> mp;
pii get_hash(int l, int r) {
    pii h = {(H[0][r] - 1ll * H[0][l - 1] * pw[0][r - l + 1] % MOD[0] + MOD[0]) % MOD[0], 
        (H[1][r] - 1ll * H[1][l - 1] * pw[1][r - l + 1] % MOD[1] + MOD[1]) % MOD[1]};
    return h;
}
     
void build_rmq(int id) {
    for (int i = 1; i <= n; i++) {
        rmq[id][0][i] = dp[id][i];
    }
    for (int i = 1; i < 20; i++) {
        for (int j = 1; j <= n; j++) {
            if (j + (1 << i) <= n + 1) {
                rmq[id][i][j] = max(rmq[id][i - 1][j], rmq[id][i - 1][j + (1 << (i - 1))]);
            }
        }
    }
}
     
int get_max(int id, int l, int r) {
    if (r <= l) return l;
    r = min(r, n + 1);
    int x = lg[r - l];
    return max(rmq[id][x][l], rmq[id][x][r - (1 << x)]);
}
     
int main() {
    for (int i = 2; i < N; i++) 
        lg[i] = lg[i >> 1] + 1;
    pw[0][0] = pw[1][0] = 1;
    for (int i = 1; i < N; i++) 
        for (int j : {0, 1})
            pw[j][i] = 1ll * pw[j][i - 1] * base[j] % MOD[j];
    scanf("%d%d", &n, &q);
    for (int i = 1; i <= n; i++) {
        scanf("%s", S);
        pii h = {0, 0};
        for (int j = 0; S[j]; j++) {
            h = {(1ll * h.F * base[0] % MOD[0] + S[j] - 'a' + 1) % MOD[0], 
                (1ll * h.S * base[1] % MOD[1] + S[j] - 'a' + 1) % MOD[1]};
            mp[h] = 1;
        }
    }
    scanf("%s", S + 1); m = strlen(S + 1);
    for (int i = 1; i <= m; i++) {
        for (int j : {0, 1}) 
            H[j][i] = (1ll * H[j][i - 1] * base[j] % MOD[j] + S[i] - 'a' + 1) % MOD[j];
    }
    swap(n, m);
    for (int i = 1; i <= n; i++) {
        int l = i - 1, r = n + 1;
        while (r - l > 1) {
            int md = (l + r) >> 1;
            if (mp.count(get_hash(i, md))) l = md;
            else r = md;
        }
        dp[0][i] = l + 1;
    }
    for (int j = 1; j < 20; j++) {
        build_rmq(j - 1);
        for (int i = 1; i <= n; i++) {
            dp[j][i] = get_max(j - 1, i, dp[j - 1][i] + 1);
        }
    }
    for (build_rmq(19); q; q--) {
        int l, r; scanf("%d%d", &l, &r); l++;
        int ret = 0, p = l;
        for (int i = 19; ~i; i--) {
            if (get_max(i, l, p + 1) <= r) ret += 1 << i, p = get_max(i, l, p + 1);
        }
        printf("%d\n", ret > n ? -1 : ret + 1);
    }
    return 0;
}

Compilation message (stderr)

Main.cpp: In function 'int main()':
Main.cpp:58:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   58 |     scanf("%d%d", &n, &q);
      |     ~~~~~^~~~~~~~~~~~~~~~
Main.cpp:60:14: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   60 |         scanf("%s", S);
      |         ~~~~~^~~~~~~~~
Main.cpp:68:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   68 |     scanf("%s", S + 1); m = strlen(S + 1);
      |     ~~~~~^~~~~~~~~~~~~
Main.cpp:90:24: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   90 |         int l, r; scanf("%d%d", &l, &r); l++;
      |                   ~~~~~^~~~~~~~~~~~~~~~

• Subtask 1: 25 / 25
• Subtask 2: 0 / 25
• Subtask 3: 0 / 50