Submission #432455

#TimeUsernameProblemLanguageResultExecution timeMemory
432455dreezyConnecting Supertrees (IOI20_supertrees)C++17
21 / 100
324 ms24084 KiB
#include "supertrees.h" #include <bits/stdc++.h> using namespace std; const int maxn = 1e3 + 5; #define pb push_back struct UnionFind{ int parent[maxn], height[maxn]; void init(int n){ for(int i =0; i<n; i++) parent[i] =i; memset(height, 0, sizeof height); } int root(int n){ if(parent[n]!= n) parent[n] = root(parent[n]); return parent[n]; } bool same(int n1, int n2){ return root(n1) == root(n2); } void join(int n1, int n2){ int r1 = root(n1); int r2 = root(n2); if(height[r1]> height[r2]){ parent[r2] = r1; height[r1] = max(height[r1]+1, height[r2]); } else{ parent[r1] = r2; height[r2] = max(height[r2]+1, height[r1]); } } }; int construct(vector<vector<int>> p) { int n = p.size(); UnionFind uf; uf.init(n); for(int i =0; i<n-1 ; i++){ for(int j = i + 1; j<n; j++){ //cout<<i<<", "<<j<<endl; if(p[i][j] > 0) uf.join(i, j); } } map<int, set<int>> trees; for(int i =0; i<n -1; i++){ for(int j =i + 1; j< n; j++){ if(p[i][j] == 0) if(uf.same(i, j))return 0; trees[uf.root(i)].insert(i); trees[uf.root(j)].insert(j); } } vector<vector<int>> ans(n, vector<int>(n, 0)); for(auto e : trees){ set<int> tree = e.second; //cout << e.first<<endl; vector<vector<int>> graph(tree.size(), vector<int>()); UnionFind uft; uft.init(n); vector<int> degree(n, 0); int endpoint = -1; vector<bool> vis(n, 0); for(int i : tree){ for(int j : tree){ if(i == j) continue; //cout << i <<", "<<j<<endl; if(p[i][j] ==1){ if(!uft.same(i, j)){ vis[i] = vis[j] = true; degree[i]++; degree[j]++; ans[i][j] = ans[j][i] =1; uft.join(i, j); } } } } for(int i : tree) if(degree[i] == 1){ endpoint = i; break; } int first = -1, last = -1; for(int i : tree){ if(vis[i]) continue; for(int j : tree){ if(vis[j]) continue; if(i == j) continue; if(p[i][j] >1){ if(!uft.same(i, j)){ if(first == -1) first = i; last = j; ans[i][j] = ans[j][i] = 1; uft.join(i, j); break; } } } } if(first == -1) continue; if(endpoint != -1){ ans[endpoint][first] = ans[first][endpoint] = 1; ans[endpoint][last] = ans[last][endpoint] =1; } else{ ans[last][first] = ans[first][last] = 1; } //cout <<endpoint<<endl; //cout << first<<", "<<last<<endl; } build(ans); return 1; }
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