Submission #428358

#TimeUsernameProblemLanguageResultExecution timeMemory
428358MarcoMeijerConnecting Supertrees (IOI20_supertrees)C++14
100 / 100
315 ms22236 KiB
#include "supertrees.h" #include <bits/stdc++.h> using namespace std; // macros typedef long long ll; typedef long double ld; typedef pair<int, int> ii; typedef pair<ll, ll> lll; typedef tuple<int, int, int> iii; typedef vector<int> vi; typedef vector<ii> vii; typedef vector<iii> viii; typedef vector<ll> vll; typedef vector<lll> vlll; #define REP(a,b,c) for(int a=int(b); a<int(c); a++) #define RE(a,c) REP(a,0,c) #define RE1(a,c) REP(a,1,c+1) #define REI(a,b,c) REP(a,b,c+1) #define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--) #define FOR(a,b) for(auto& a : b) #define all(a) a.begin(), a.end() #define INF 1e9 #define EPS 1e-9 #define pb push_back #define popb pop_back #define fi first #define se second #define sz size() mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count()); const int MX=2000; int n; struct DSU { int p[MX], r[MX]; vi dif[MX]; void build() { RE(i,n) p[i]=i, r[i]=0, dif[i]={i}; } int get(int i) {return i==p[i] ? i : p[i]=get(p[i]);} bool isSame(int i, int j) {return get(i) == get(j);} void link(int i, int j) { i = get(i), j = get(j); if(dif[i].size() > dif[j].size()) swap(i,j); FOR(x,dif[i]) dif[j].pb(x); if(i != j) { if(r[i] > r[j]) { p[j] = i; swap(dif[i],dif[j]); } else { p[i] = j; if(r[i] == r[j]) r[j]++; } } } } dsu1, dsu2; int construct(vector<vi> p) { n = p.size(); vector<vi> answer(n,vi(n,0)); dsu1.build(); RE(i,n) RE(j,n) { if(p[i][j] == 1 && !dsu1.isSame(i,j)) dsu1.link(i,j), answer[i][j] = answer[j][i] = 1; } RE(i,n) RE(j,n) if(p[i][j] == 0 && dsu1.isSame(i,j)) return 0; dsu2.build(); RE(i,n) RE(j,n) { if(p[i][j] == 2 && !dsu2.isSame(dsu1.get(i),dsu1.get(j))) dsu2.link(dsu1.get(i),dsu1.get(j)); } RE(i,n) if(dsu2.get(i) == i) { if(dsu2.dif[i].size() == 1) continue; if(dsu2.dif[i].size() == 2) return 0; RE(u,dsu2.dif[i].size()) { int v = (u+1)%dsu2.dif[i].size(); int x = dsu2.dif[i][u]; int y = dsu2.dif[i][v]; answer[x][y] = answer[y][x] = 1; } } RE(i,n) RE(j,n) if(p[i][j] == 0 && dsu2.isSame(dsu1.get(i),dsu1.get(j))) return 0; RE(i,n) RE(j,n) if(p[i][j] == 3) return 0; build(answer); return 1; }
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