This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "supertrees.h"
#include <bits/stdc++.h>
using namespace std;
// macros
typedef long long ll;
typedef long double ld;
typedef pair<int, int> ii;
typedef pair<ll, ll> lll;
typedef tuple<int, int, int> iii;
typedef vector<int> vi;
typedef vector<ii> vii;
typedef vector<iii> viii;
typedef vector<ll> vll;
typedef vector<lll> vlll;
#define REP(a,b,c) for(int a=int(b); a<int(c); a++)
#define RE(a,c) REP(a,0,c)
#define RE1(a,c) REP(a,1,c+1)
#define REI(a,b,c) REP(a,b,c+1)
#define REV(a,b,c) for(int a=int(c-1); a>=int(b); a--)
#define FOR(a,b) for(auto& a : b)
#define all(a) a.begin(), a.end()
#define INF 1e9
#define EPS 1e-9
#define pb push_back
#define popb pop_back
#define fi first
#define se second
#define sz size()
mt19937_64 rng(chrono::steady_clock::now().time_since_epoch().count());
const int MX=2000;
int n;
struct DSU {
int p[MX], r[MX];
vi dif[MX];
void build() {
RE(i,n) p[i]=i, r[i]=0, dif[i]={i};
}
int get(int i) {return i==p[i] ? i : p[i]=get(p[i]);}
bool isSame(int i, int j) {return get(i) == get(j);}
void link(int i, int j) {
i = get(i), j = get(j);
if(dif[i].size() > dif[j].size()) swap(i,j);
FOR(x,dif[i]) dif[j].pb(x);
if(i != j) {
if(r[i] > r[j]) {
p[j] = i;
swap(dif[i],dif[j]);
} else {
p[i] = j;
if(r[i] == r[j]) r[j]++;
}
}
}
} dsu1, dsu2;
int construct(vector<vi> p) {
n = p.size();
vector<vi> answer(n,vi(n,0));
dsu1.build();
RE(i,n) RE(j,n) {
if(p[i][j] == 1 && !dsu1.isSame(i,j))
dsu1.link(i,j), answer[i][j] = answer[j][i] = 1;
}
RE(i,n) RE(j,n) if(p[i][j] == 0 && dsu1.isSame(i,j)) return 0;
dsu2.build();
RE(i,n) RE(j,n) {
if(p[i][j] == 2 && !dsu2.isSame(dsu1.get(i),dsu1.get(j)))
dsu2.link(dsu1.get(i),dsu1.get(j));
}
RE(i,n) if(dsu2.get(i) == i) {
if(dsu2.dif[i].size() == 1)
continue;
if(dsu2.dif[i].size() == 2)
return 0;
RE(u,dsu2.dif[i].size()) {
int v = (u+1)%dsu2.dif[i].size();
int x = dsu2.dif[i][u];
int y = dsu2.dif[i][v];
answer[x][y] = answer[y][x] = 1;
}
}
RE(i,n) RE(j,n) if(p[i][j] == 0 && dsu2.isSame(dsu1.get(i),dsu1.get(j))) return 0;
RE(i,n) RE(j,n) if(p[i][j] == 3) return 0;
build(answer);
return 1;
}
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