# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
42402 | Aidyn_A | Longest beautiful sequence (IZhO17_subsequence) | C++14 | 3899 ms | 136728 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,sse3,sse4,popcnt,abm,mmx")
#include <stdio.h>
#include <bits/stdc++.h>
#define pb push_back
#define pf push_front
#define pp pop_back
#define sz(a) (int)(a.size())
#define mp make_pair
#define F first
#define S second
#define next _next
#define prev _prev
#define left _left
#define right _right
#define y1 _y1
#define all(x) x.begin(), x.end()
#define what_is(x) #x << " is " << (x)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int N = (int)1e5 + 123;
const ll INF = (ll)1e18 + 123;
const int inf = (int)1e9 + 123;
const int MOD = (int)1e9 + 7;
int n, a[N], b[N];
int half = 10;
pii dp[(1<<10) + 123][(1<<10) + 123][11];
int now[N], pr[N];
int main() {
scanf("%d", &n);
for(int i = 1; i <= n; i ++)
scanf("%d", &a[i]);
for(int i = 1; i <= n; i ++)
scanf("%d", &b[i]);
int res = -1, res_p = -1;
for(int i = 1; i <= n; i ++) {
now[i] = 1;
//GET
int j = 0, origin = (a[i] >> half), firsthalf = (a[i] >> half);
for(int mask = 0; mask < (1 << half); mask ++) {
int left = b[i] - __builtin_popcount(origin & mask);
if(left >= 0 && left <= 10) {
int lasthalf = (a[i] & ((1 << half) - 1));
if(dp[mask][lasthalf][left].F + 1 > now[i]) {
now[i] = dp[mask][lasthalf][left].F + 1;
j = dp[mask][lasthalf][left].S;
}
}
}
pr[i] = j;
for(int mask = 0; mask < (1 << half); mask ++) {
int changed = __builtin_popcount(a[i] & mask);
if(dp[firsthalf][mask][changed].F < now[i])
dp[firsthalf][mask][changed] = {now[i], i};
}
if(now[i] > res)
res = now[i], res_p = i;
}
printf("%d\n", res);
vector<int> v;
while(res_p > 0) {
v.pb(res_p);
res_p = pr[res_p];
}
for(int i = sz(v) - 1; i >= 0; i --)
printf("%d ", v[i]);
return 0;
}
Compilation message (stderr)
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