| # | 제출 시각 | 아이디 | 문제 | 언어 | 결과 | 실행 시간 | 메모리 | 
|---|---|---|---|---|---|---|---|
| 42371 | Aidyn_A | Longest beautiful sequence (IZhO17_subsequence) | C++14 | 12 ms | 2104 KiB | 
이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <stdio.h>
#include <bits/stdc++.h>			
#define pb push_back
#define pf push_front
#define pp pop_back
#define sz(a) (int)(a.size())
#define mp make_pair
#define F first
#define S second
#define next _next
#define prev _prev
#define left _left
#define right _right
#define y1 _y1
#define all(x) x.begin(), x.end()
#define what_is(x) #x << " is " << (x)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
const int N = (int)1e6 + 123;
const ll INF = (ll)1e18 + 123;
const int inf = (int)1e9 + 123;
const int MOD = (int)1e9 + 7;
void megaRandom() {
	unsigned int FOR;
 	asm("rdtsc" : "=A"(FOR));
  srand(FOR);
}
int n, a[N], b[N];
pii dp[(1<<10) + 123][(1<<10) + 123][11];
int now[N], pr[N];
int main() {
	megaRandom();
	scanf("%d", &n);//cin >> n;
	for(int i = 1; i <= n; i ++) 
		scanf("%d", &a[i]);//cin >> a[i];
	for(int i = 1; i <= n; i ++) 
		scanf("%d", &b[i]);//cin >> b[i];
	int res = 0, res_p = -1;
	for(int i = 1; i <= n; i ++) {
		//GET
		int j = -1;
		for(int mask = 0; mask < (1 << 10); mask ++) {
			int origin = (mask << 10);
			int left = b[i] - __builtin_popcount(origin & a[i]);
			if(left >= 0) {
				int lasthalf = (a[i] & ((1 << 10) - 1));
				if(dp[mask][lasthalf][left].F + 1 > now[i]) {
					now[i] = dp[mask][lasthalf][left].F + 1;				
					j = dp[mask][lasthalf][left].S;  
				}
			}
		}
		pr[i] = j;
		//cout << "i: " << i << " now: " << now[i] << "\n";   
		//UPDATE
		for(int mask = 0; mask < (1 << 10); mask ++) {
			int firsthalf = (a[i] >> 10);
			int changed = __builtin_popcount(a[i] & mask);
			if(dp[firsthalf][mask][changed].F < now[i]) {
				dp[firsthalf][mask][changed] = {now[i], i};
			}
		}
		if(now[i] > res)
			res = now[i], res_p = i;
	}
	printf("%d\n", res);//cout << res << "\n";           
	vector<int> v;
	while(res_p > 0) {
		v.pb(res_p);
		res_p = pr[res_p];		
	}
	reverse(all(v));
	for(auto aa : v)
		printf("%d ", aa);//cout << aa << ' ';
	return 0;  
}
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