Submission #42321

#	Time	Username	Problem	Language	Result	Execution time	Memory
42321		minkank	역사적 조사 (JOI14_historical)	C++14	100 / 100	249 ms	66044 KiB

historic

#include <bits/stdc++.h>
using namespace std;

const int N = 1e5 + 5;

#define st first
#define nd second
typedef pair<int, int> ii;

ii qu[N];
int n, m, a[N], Time, b[N];
long long ans[N];
vector<int> Q[N];
map<int, int> sax;
int cnt[N], cnt2[N];

bool cmp(int a, int b) { return qu[a].nd < qu[b].nd; }

signed main() {
	ios::sync_with_stdio(false); cin.tie(0);
	cin >> n >> m;
	for(int i = 1; i <= n; ++i) {
		cin >> a[i];
		if(!sax[a[i]]) sax[a[i]] = ++Time;
		b[i] = sax[a[i]];
	}
	for(int i = 1; i <= m; ++i)
		cin >> qu[i].st >> qu[i].nd, Q[(long long)(qu[i].st / sqrt(n))].push_back(i);
	for(int i = 0; i <= sqrt(n); ++i) {
		sort(Q[i].begin(), Q[i].end(), cmp);
		int maxL = 0;
		for(int j = 0; j < Q[i].size(); ++j) maxL = max(maxL, qu[Q[i][j]].st);
		int cur = maxL;
		long long curmx = 0;
		memset(cnt, 0, sizeof cnt);
		for(int j = 0; j < Q[i].size(); ++j) {
			int id = Q[i][j], L = qu[id].st, R = qu[id].nd;
			while(cur <= R) {
				int x = a[cur];
				cnt[b[cur]]++; curmx = max(curmx, 1LL * cnt[b[cur]] * x);
				cur++;
			}
			ans[id] = curmx;
			for(int k = L; k < min(maxL, R + 1); ++k) {
				int x = a[k];
				cnt2[b[k]]++; ans[id] = max(ans[id], 1LL * (cnt2[b[k]] + cnt[b[k]]) * x);
			}
			for(int k = L; k < min(maxL, R + 1); ++k) {
				int x = a[k];
				cnt2[b[k]]--;
			}
		}
	}
	for(int i = 1; i <= m; ++i) printf("%lld\n", ans[i]);
}

Compilation message (stderr)

historic.cpp: In function 'int main()':
historic.cpp:32:20: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
   for(int j = 0; j < Q[i].size(); ++j) maxL = max(maxL, qu[Q[i][j]].st);
                    ^
historic.cpp:36:20: warning: comparison between signed and unsigned integer expressions [-Wsign-compare]
   for(int j = 0; j < Q[i].size(); ++j) {
                    ^
historic.cpp:49:9: warning: unused variable 'x' [-Wunused-variable]
     int x = a[k];
         ^

• Subtask 1: 5 / 5
• Subtask 2: 10 / 10
• Subtask 3: 25 / 25
• Subtask 4: 60 / 60