Submission #422065

#	Time	Username	Problem	Language	Result	Execution time	Memory
422065		2fat2code	Financial Report (JOI21_financial)	C++17	100 / 100	634 ms	29860 KiB

Main

#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define ld long double
#define all(a) (a).begin(), (a).end()
//#pragma GCC optimize("O3")
//#pragma GCC optimize("Ofast")
#define fr first
#define sc second
#define int long long
#define rc(s) return cout<<s,0
#define rcc(s) cout<<s,exit(0)

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

const int nmax = 300005;

int n, a[nmax], d, tree[4*nmax], tree2[4*nmax], lazy[4*nmax];
vector<int>vecc;

void build(int l, int r, int nod){
    if(l == r){
        tree[nod] = a[l];
    }
    else{
        int mid = l + (r - l) / 2;
        build(l, mid, 2*nod);
        build(mid + 1, r, 2*nod+1);
        tree[nod] = min(tree[2*nod], tree[2*nod+1]);
    }
}

int query1(int l, int r, int le, int ri, int nod){
    if(l > ri || r < le) return 1e18;
    else if(l >= le && r <= ri) return tree[nod];
    else{
        int mid = l + (r - l) / 2;
        return min(query1(l, mid, le, ri, 2*nod), query1(mid + 1, r, le, ri, 2*nod + 1));
    }
}

void push(int l, int r, int nod){
    if(lazy[nod] == 1){
        tree2[nod] = 0;
        if(l != r){
            lazy[2*nod] = 1;
            lazy[2*nod+1] = 1;
        }
        lazy[nod] = 0;
    }
}

void update2(int l, int r, int le, int ri, int nod){
    push(l, r, nod);
    if(r < le || l > ri) return;
    else if(l >= le && r <= ri){
        lazy[nod] = 1;
        push(l, r, nod);
    }
    else{
        int mid = l + (r - l) / 2;
        update2(l, mid, le, ri, 2*nod);
        update2(mid+1, r, le, ri, 2*nod + 1);
        tree2[nod] = max(tree2[2*nod], tree2[2*nod + 1]);
    }
}

int query2(int l, int r, int le, int ri, int nod){
    push(l, r, nod);
    if(l > ri || r < le){
        return 0;
    }
    else if(l >= le && r <= ri){
        return tree2[nod];
    }
    else{
        int mid = l + (r - l) / 2;
        return max(query2(l, mid, le, ri, 2*nod), query2(mid+1, r, le, ri, 2*nod +1));
    }
}

void update3(int l, int r, int pos, int val, int nod){
    push(l, r, nod);
    if(l == r){
        tree2[nod] = max(tree2[nod], val);
    }
    else{
        int mid = l + (r - l) / 2;
        tree2[nod] = max(tree2[nod], val);
        if(pos <= mid){
            update3(l, mid, pos, val, 2*nod);
        }
        else{
            update3(mid + 1, r, pos, val, 2*nod + 1);
        }
    }
}

int32_t main(){
    //ios_base::sync_with_stdio(false);cin.tie(0);cerr.tie(0);cout.tie(0);
   // freopen("input.in", "r", stdin);
    cin >> n >> d;
    for(int i=1;i<=n;i++){
        cin >> a[i];
        vecc.push_back(a[i]);
    }
    sort(all(vecc));
    vecc.resize(unique(all(vecc)) - vecc.begin());
    for(int i=1;i<=n;i++) a[i] = lower_bound(all(vecc), a[i]) - vecc.begin() + 1LL;
    build(1, n, 1);
    int nn = (int)vecc.size();
    for(int i=1;i<=n;i++){
        if(i >= 2){
            int curr = query1(1, n, max(1LL, i - d), i - 1, 1);
            if(curr >= 2LL) update2(1, nn, 1, curr - 1LL, 1);
        }
        int val = 1LL;
        if(a[i] >= 2LL){
            val += query2(1, nn, 1, a[i] - 1LL, 1);
        }
        update3(1, nn, a[i], val, 1);
    }
    cout << tree2[1];
}

// 1. Solve the problem
// 2. ???
// 3. Profit

• Subtask 1: 14 / 14
• Subtask 2: 14 / 14
• Subtask 3: 20 / 20
• Subtask 4: 12 / 12
• Subtask 5: 5 / 5
• Subtask 6: 35 / 35