/*input
2
4
bbcb
aada
aada
3
abc
bbb
bbb
*/
#include "monster.h"
#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> indexed_set;
#pragma GCC optimize("Ofast")
//order_of_key #of elements less than x
// find_by_order kth element
typedef long long int ll;
#define ld double
#define pii pair<ll,ll>
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x) (ll)x.size()
const ll maxn=2e5+5;
const ll maxlg=__lg(maxn)+2;
const ll INF64=4e17;
const int INF=0x3f3f3f3f;
const ll MOD2=3006703054056749LL;
const ll MOD=1e9+7;
const ld PI=acos(-1);
const ld eps=1e-4;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
ll mult(ll a,ll b){
ll res=0;
while(b){
if(b&1) res+=a,res%=MOD;
a+=a;
a%=MOD;
b>>=1;
}
return res;
}
ll mypow(ll a,ll b){
ll res=1;
while(b){
if(b&1) res=mult(res,a);
a=mult(a,a);
b/=2;
}
return res;
}
int tmp[maxn],arr[maxn];
map<pii,bool> mp;
bool cmp(int a,int b){
if(mp.count({a,b})) return mp[{a,b}];
return mp[{a,b}]=Query(a,b);
}
void srt(int l,int r){
if(l==r) return;
int mid=(l+r)/2;
srt(l,mid);
srt(mid+1,r);
int p1=l,p2=mid+1,p=l;
while(p1<=mid and p2<=r){
if(cmp(arr[p1],arr[p2])) tmp[p++]=arr[p1++];
else tmp[p++]=arr[p2++];
}
while(p1<=mid) tmp[p++]=arr[p1++];
while(p2<=r) tmp[p++]=arr[p2++];
for(int i=l;i<=r;i++) arr[i]=tmp[i];
}
vector<int> Solve(int n) {
REP(i,n) arr[i]=i;
srt(0,n-1);
vector<int> ans(n);
vector<int> v;
REP1(i,n-1){
if(!cmp(arr[0],arr[i])){
v.pb(i);
}
}
int mx=0;
if(sz(v)==1) mx=v[0];
else mx=v[sz(v)-2];
int cur=n-1;
for(int i=mx;i>=0;i--){
ans[arr[i]]=(cur--);
}
int p=0;
v.clear();
for(int i=mx+1;i<n;i++){
v.pb(arr[i]);
if(!cmp(arr[p],arr[i])){
reverse(ALL(v));
p=v.back();
for(auto x:v) ans[x]=(cur--);
v.clear();
}
}
return ans;
}
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
1 ms |
200 KB |
Wrong Answer [3] |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
1 ms |
200 KB |
Wrong Answer [3] |
| 2 |
Halted |
0 ms |
0 KB |
- |
| # |
Verdict |
Execution time |
Memory |
Grader output |
| 1 |
Incorrect |
121 ms |
892 KB |
Wrong Answer [3] |
| 2 |
Halted |
0 ms |
0 KB |
- |
