Submission #419577

#	Time	Username	Problem	Language	Result	Execution time	Memory
419577		amoo_safar	Bodyguard (JOI21_bodyguard)	C++17	0 / 100	1880 ms	382668 KiB

bodyguard

// vaziat meshki-ghermeze !
#include <bits/stdc++.h>

#define pb push_back
#define F first
#define S second
#define all(x) x.begin(), x.end()
#define debug(x) cerr << #x << " : " << x << '\n'

using namespace std;

typedef long long ll;
typedef long double ld;
typedef string str;
typedef pair<ll, ll> pll;
typedef pair<int, int> pii;

const ll Mod = 1000000007LL;
const int N = 6e3 + 10;
const int Q = 3e6 + 10;
const ll Inf = 2242545357980376863LL;
const ll Log = 30;

// X : X + T;
// Y : X - T;

vector<int> cx, cy;

void Add(int x, int y){ cx.pb(x); cy.pb(y); }
void Uni(vector<int>& C){
	sort(all(C));
	C.resize(unique(all(C)) - C.begin());
}
void Init(){ Uni(cx); Uni(cy); }
pii Get(int x, int y){
	x = lower_bound(all(cx), x) - cx.begin();
	y = lower_bound(all(cy), y) - cy.begin();
	return {x, y};
}
int T[N], T2[N], A[N], B[N], C[N], P[Q], X[Q];

int up[N][N], rt[N][N];
ll dp[N][N];

int main(){
	ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);
	int n, q;
	cin >> n >> q;
	
	for(int i = -3000; i <= 3000; i++) Add(i, i);

	for(int i = 1; i <= n; i++){
		cin >> T[i] >> A[i] >> B[i] >> C[i];
		T2[i] = abs(A[i] - B[i]) + T[i];
		C[i] /= 2;
		// Add(T[i] + A[i], T[i] - A[i]);
		// Add(T2[i]+ B[i],T2[i] - B[i]);
	}
	Add(Q, Q);
	for(int i = 1; i <= q; i++){
		cin >> P[i] >> X[i];
		// Add(P[i] + X[i], P[i] - X[i]);
	}
	Init();
	for(int i = 1; i <= n; i++){
		pii st = Get(T[i] + A[i], T[i] - A[i]);
		pii fn = Get(T2[i]+ B[i],T2[i] - B[i]);
		// cerr << 
		if(st.F == fn.F){
			for(int _i = st.S; _i < fn.S; _i++)
				up[st.F][_i] = max(up[st.F][_i], C[i]);
		} else {
			for(int _i = st.F; _i < fn.F; _i++)
				rt[_i][st.S] = max(rt[_i][st.S], C[i]);
		}
	}
	int nx = cx.size(), ny = cy.size();
	for(int i = nx - 2; i >= 0; i--)
		for(int j = ny - 2; j >= 0; j--)
			dp[i][j] = max(1ll * up[i][j] * (cy[j + 1] - cy[j]) + dp[i][j + 1], 1ll * rt[i][j] * (cx[i + 1] - cx[i]) + dp[i + 1][j]);
	for(int i = 1; i <= q; i++){
		pii st = Get(P[i] + X[i], P[i] - X[i]);
		cout << dp[st.F][st.S] << '\n';
	}
	return 0;
}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 7
• Subtask 3: 0 / 15
• Subtask 4: 0 / 20
• Subtask 5: 0 / 53