#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef pair < int, int > PII;
#define F first
#define S second
#define mkp make_pair
#define eb emplace_back
#define all(a) a.begin(), a.end()
#define sz(a) (int)a.size()
#define y1 kekek
#define forn(x, a, b) for (int x = a; x <= b; ++x)
#define for1(x, a, b) for (int x = a; x >= b; --x)
const ll ool = 1e18 + 9;
const int N = 2e3 + 6, oo = 1e9 + 9, base = 1e9 + 7;
int n, A, B, a[N], d[N][N], d2[55][22][555];
ll ans = ool;
bool bit[22];
bool check(ll mask1, ll mask2, int pos) {
mask1 >>= 1ll * pos;
mask2 >>= 1ll * pos;
return ((mask1 | mask2) == mask1);
}
bool calc(ll mask, int pos) {
d[0][0] = 1;
forn(i, 1, n) {
forn(j, 1, B) {
d[i][j] = 0;
ll sum = 0;
for1(k, i, 1) {
sum += a[k];
// if (pos == 35 && i == 1 && j == 1) cerr << mask << " " << sum << " " << check(mask, sum, pos) << "\n";
if (!check(mask, sum, pos)) continue;
d[i][j] |= d[k - 1][j - 1];
}
}
}
forn(i, A, B) {
if (d[n][i]) return 1;
}
return 0;
}
int main() {
#ifdef krauch
freopen("input.txt", "r", stdin);
#endif
cin >> n >> A >> B;
forn(i, 1, n) {
cin >> a[i];
}
if (A) {
ll ans = 0;
for1(i, 41, 0) {
ans |= (1ll << i);
bool res = calc(ans, i);
ans ^= (1ll << i);
if (!res) ans |= (1ll << (i + 1));
}
if (!calc(ans, 0)) ans++;
cout << ans << "\n";
return 0;
}
forn(j, 0, 2000) d[0][j] = oo;
d[0][0] = 0;
forn(i, 1, n) {
int sum = 0;
forn(j, 0, 2000) d[i][j] = oo;
for1(j, i, 1) {
sum += a[j];
forn(k, 0, 2000) {
d[i][k | sum] = min(d[i][k | sum], d[j - 1][k] + 1);
}
}
}
int pos = 2000;
forn(i, 0, 2000) {
if (d[n][i] <= B) {
pos = i;
break;
}
}
cout << pos << "\n";
return 0;
}
