Submission #414573

#TimeUsernameProblemLanguageResultExecution timeMemory
414573Aldas25Potatoes and fertilizers (LMIO19_bulves)C++14
0 / 100
246 ms262148 KiB
#pragma GCC target ("avx2") #pragma GCC optimize ("O2") #pragma GCC optimize ("unroll-loops") #include <bits/stdc++.h> using namespace std; #define FAST_IO ios_base::sync_with_stdio(0); cin.tie(0) #define FOR(i, a, b) for(int i = (a); i <= (b); i++) #define REP(n) FOR(O, 1, (n)) #define pb push_back #define f first #define s second typedef long double ld; typedef long long ll; typedef pair<int, int> pii; typedef pair<int, pii> piii; typedef vector<int> vi; typedef vector<pii> vii; typedef vector<ll> vl; typedef vector<piii> viii; const int MAXN = 500100, MAXK = 30; //const ll MOD = 998244353; const ll INF = 4e18; const ld PI = asin(1) * 2; int n; ll a[MAXN], b[MAXN], dif[MAXN], pref[MAXN]; ll dp[3100][31000]; int main() { FAST_IO; cin >> n; FOR(i, 1, n) cin >> a[i] >> b[i]; FOR(i, 1, n) { dif[i] = a[i]-b[i]; pref[i] = pref[i-1] + dif[i]; } //ll mx = pref[n]; ll mx = 31000-1; FOR(i, 1, n) FOR(j, 0, mx) { if (j > 0) dp[i][j] = dp[i][j-1]; else dp[i][j] = INF; dp[i][j] = min(dp[i][j], dp[i-1][j] + abs(j - pref[i])); } cout << dp[n][pref[n]] << "\n"; return 0; }
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