Submission #414476

#TimeUsernameProblemLanguageResultExecution timeMemory
414476grtPalembang Bridges (APIO15_bridge)C++17
63 / 100
2098 ms3304 KiB
#include <bits/stdc++.h> #define ST first #define ND second #define PB push_back using namespace std; using ll = long long; using pi = pair<int,int>; using vi = vector<int>; const int nax = 100 * 1000 + 10; const ll INF = 1e18; int n, m, k; int opn[nax], clo[nax]; vi all; ll add = 0; int main() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> k >> n; for(int i = 0; i < n; ++i) { char t1, t2; int d1, d2; cin >> t1 >> d1 >> t2 >> d2; add += abs(d1 - d2); if(t1 != t2) { opn[m] = min(d1, d2); clo[m] = max(d1, d2); all.PB(d1); all.PB(d2); m++; } } sort(all.begin(), all.end()); if(m == 0) { cout << add << "\n"; return 0; } if(k == 1) { sort(opn, opn + m); sort(clo, clo + m); int ptr = 0, ptr2 = 0; ll Lsum = 0, Rsum = 0; ll ans = INF; for(int i = 0; i < m; ++i) Rsum += opn[i]; for(int x : all) { while(ptr2 < m && clo[ptr2] < x) { Lsum += clo[ptr2]; ptr2++; } while(ptr < m && opn[ptr] < x) { Rsum -= opn[ptr]; ptr++; } ll d = (ll)x * ptr2 - Lsum - (ll)x * (m - ptr) + Rsum; ans = min(ans, d); } cout << ans * 2 + add + m << "\n"; } else { ll ans = INF; for(int x : all) { ll cur = 0; priority_queue<pi>PQ; vi nopn, nclo; for(int i = 0; i < m; ++i) { if(opn[i] <= x) { if(clo[i] >= x) continue; cur += abs(x - clo[i]); } else { PQ.push({-(clo[i] + opn[i] - x), opn[i]}); nopn.PB(opn[i]); nclo.PB(clo[i]); } } sort(nopn.begin(), nopn.end()); sort(nclo.begin(), nclo.end()); int ptr = 0, ptr2 = 0; ll Lsum = 0, Rsum = 0; int lft = 0; for(int i = 0; i < (int)nopn.size(); ++i) Rsum += nopn[i]; for(int y : all) { if(y < x) continue; while(ptr2 < (int)nclo.size() && nclo[ptr2] < y) { Lsum += nclo[ptr2]; ptr2++; lft++; } while(ptr < (int)nopn.size() && nopn[ptr] < y) { Rsum -= nopn[ptr]; ptr++; } while(!PQ.empty()) { auto z = PQ.top(); if(y < -z.ST) break; PQ.pop(); lft--; cur += z.ND - x; z.ST = -z.ST; Lsum -= (z.ST - z.ND + x); } ll d = cur + Rsum - (ll)y * ((int)nopn.size() - ptr) + (ll)lft * y - Lsum; ans = min(ans, d); } } cout << ans * 2 + add + m << "\n"; } }
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