Submission #410947

#	TimeUTC-0	Username	Problem	Language	Result	Execution time	Memory
410947	2021-05-24 00:21:36	JerryLiu06	Synchronization (JOI13_synchronization)	C++17	100 / 100	322 ms	24260 KiB

synchronization

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#include <bits/stdc++.h>
 
using namespace std;
 
using ll = long long;
using db = long double;
using str = string;
 
using pi = pair<int, int>;
using pl = pair<ll, ll>;
using pd = pair<db, db>;
 
using vi = vector<int>;
using vb = vector<bool>;
using vl = vector<ll>;
using vd = vector<db>;
using vs = vector<str>;
using vpi = vector<pi>;
using vpl = vector<pl>;
using vpd = vector<pd>;
 
#define mp make_pair
#define f first
#define s second
#define sz(x) (int)(x).size()
#define bg(x) begin(x)
#define all(x) bg(x), end(x)
#define sor(x) sort(all(x))
#define ft front()
 
 
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Compilation message (stderr)

synchronization.cpp: In function 'void DFS(int, int)':
synchronization.cpp:42:20: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   42 | #define EACH(a, x) for (auto& a : x)
      |                    ^~~
synchronization.cpp:57:5: note: in expansion of macro 'EACH'
   57 |     EACH(Y, adj[X]) if (Y != P) DFS(Y, X); out[X] = timer;
      |     ^~~~
synchronization.cpp:57:44: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   57 |     EACH(Y, adj[X]) if (Y != P) DFS(Y, X); out[X] = timer;
      |                                            ^~~
synchronization.cpp: In function 'int findRoot(int)':
synchronization.cpp:40:22: warning: this 'for' clause does not guard... [-Wmisleading-indentation]
   40 | #define ROF(i, a, b) for (int i = (b) - 1; i >= (a); i--)
      |                      ^~~
synchronization.cpp:41:19: note: in expansion of macro 'ROF'
   41 | #define R0F(i, a) ROF(i, 0, a)
      |                   ^~~
synchronization.cpp:68:5: note: in expansion of macro 'R0F'
   68 |     R0F(i, 20) if (lift[X][i] && query(in[lift[X][i]]) == query(in[X])) X = lift[X][i]; return X;
      |     ^~~
synchronization.cpp:68:89: note: ...this statement, but the latter is misleadingly indented as if it were guarded by the 'for'
   68 |     R0F(i, 20) if (lift[X][i] && query(in[lift[X][i]]) == query(in[X])) X = lift[X][i]; return X;
      |                                                                                         ^~~~~~

• Subtask 1: 10 / 10
• Subtask 2: 20 / 20
• Subtask 3: 10 / 10
• Subtask 4: 20 / 20
• Subtask 5: 40 / 40