#include <bits/stdc++.h>
using namespace std;
template<class T, class U>
void ckmin(T &a, U b)
{
if (a > b) a = b;
}
template<class T, class U>
void ckmax(T &a, U b)
{
if (a < b) a = b;
}
#define MP make_pair
#define PB push_back
#define LB lower_bound
#define UB upper_bound
#define fi first
#define se second
#define SZ(x) ((int) (x).size())
#define ALL(x) (x).begin(), (x).end()
#define FOR(i, a, b) for (auto i = (a); i < (b); i++)
#define FORD(i, a, b) for (auto i = (a) - 1; i >= (b); i--)
const long long LLINF = 3e18;
const int MAXN = 100013;
typedef long long ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef vector<int> vi;
typedef vector<ll> vl;
typedef vector<pii> vpi;
typedef vector<pll> vpl;
int N, M;
map<int, vector<array<int, 3> > > edge[MAXN];
int color[MAXN];
int cost[MAXN];
map<int, ll> sum[MAXN];
//you can only save it if its color is unique or its color is twice and you just used one of them & paid.
ll dist[MAXN];
map<int, ll> special[MAXN];
priority_queue<array<ll, 3>, vector<array<ll, 3> >, greater<array<ll, 3> > > pq;
ll ans;
//distance, vertex, edge
int32_t main()
{
cout << fixed << setprecision(12);
cerr << fixed << setprecision(4);
ios_base::sync_with_stdio(false); cin.tie(0);
cin >> N >> M;
FOR(i, 0, M)
{
int u, v, c, d;
cin >> u >> v >> c >> d; u--; v--;
edge[u][c].PB({v, d, i});
edge[v][c].PB({u, d, i});
sum[u][c] += d;
sum[v][c] += d;
color[i] = c;
cost[i] = d;
// edge[u].PB({v, c, d});
// edge[v].PB({u, c, d});
}
FOR(u, 0, N)
{
for (auto &p : edge[u])
{
sort(ALL(p.se), [&](array<int, 3> a, array<int, 3> b)
{
return a[1] > b[1];
});
// for (auto e : p.se)
// {
// cerr << "EDGE " << u << ' ' << e.fi << ' ' << " color " << p.fi << " dis " << e.se << endl;
// }
}
}
fill(dist, dist + N, LLINF);
dist[0] = 0;
pq.push({0, 0, -1});
while(!pq.empty())
{
ll d = pq.top()[0]; int u = pq.top()[1], c = pq.top()[2];
pq.pop();
if (c != -1)
{
if (d != special[u][c]) continue;
int cl = color[c];
int it = 0;
for (auto e : edge[u][cl]) //you can take an edge for free if you just came here w edge of that color && deg is 2.
{
// #warning cut time complexity by limiting it to two iterations?
int v = e[0]; ll dis = e[1]; int eid = e[2];
ll nd = d + min(dis, sum[u][cl] - dis - cost[c]);
if (dist[v] > nd)
{
dist[v] = nd;
pq.push({nd, v, -1});
}
it++;
if (it > 3) break;
// if (special[v].find(eid) == special[v].end() || special[v])
}
}
else
{
if (d != dist[u]) continue;
for (auto p : edge[u])
{
int cl = p.fi;
for (auto e : p.se)
{
int v = e[0]; ll dis = e[1]; int eid = e[2];
//no guarantees -> you just need to make this the unique color from u.
ll nd = d + min(dis, sum[u][cl] - dis);
// ll nd = d + dis;
if (dist[v] > nd)
{
dist[v] = nd;
pq.push({nd, v, -1});
}
//but also set the special distance. here you have to actually pay to set this.
nd = d + dis;
if ((special[v].find(eid) == special[v].end() || special[v][eid] > nd))
{
special[v][eid] = nd;
pq.push({nd, v, eid});
}
}
}
}
}
ans = dist[N - 1];
if (ans >= LLINF) ans = -1;
cout << ans << '\n';
return 0;
}
