//apig's property
//Happiness can be found, even in the darkest of times, if one only remembers to turn on the light
//El Pueblo Unido Jamas Sera Vencido
//The saddest thing about betrayal? is that it never comes from your enemies
//Do or do not... there is no try
//Billions of bilious blue blistering barnacles in a thundering typhoon!
#include<bits/stdc++.h>
#define fast ios_base::sync_with_stdio(0) , cin.tie(0) , cout.tie(0)
#define F first
#define S second
#define pb push_back
#define vll vector< ll >
#define vi vector< int >
#define pll pair< ll , ll >
#define pi pair< int , int >
#define all(s) s.begin() , s.end()
#define sz(s) s.size()
#define str string
#define md ((s + e) / 2)
#define mid ((l + r) / 2)
#define msdp(dp) memset(dp , -1 , sizeof dp)
#define mscl(dp) memset(dp , 0 , sizeof dp)
#define C continue
#define R return
#define B break
#define lx node * 2
#define rx node * 2 + 1
#define br(o) o ; break
#define co(o) o ; continue
using namespace std;
typedef int ll;
ll q, a[55555] , k, l, m, n, o, p;
const ll mod = 1e9+7;
str s;
ll tree[50000 * 4 + 16] ;
void build(ll s, ll e , ll node){
if(s == e){
tree[node] = a[s] ;
R ;
}
build(s , md , lx) , build(md + 1 , e , rx) ;
tree[node] = min(tree[lx] , tree[rx]) ;
}
void update(ll s , ll e , ll node , ll idx , ll val){
if(s > idx || e < idx)R ;
if(s == e){
tree[node] = val ;
R ;
}
update(s , md , lx , idx , val) , update(md + 1 , e , rx , idx , val) ;
tree[node] = min(tree[lx] , tree[rx]) ;
}
ll query(ll s , ll e , ll node , ll l , ll r){
if(r < l || s > r || e < l)R mod ;
if(l <= s && e <= r)R tree[node] ;
R min(query(s , md , lx , l , r) , query(md + 1 , e , rx , l , r)) ;
}
ll op(ll l , ll r){
if(r - 2 >= m || l - 1 >= m)R 0 ;
if(l < 0 || r < 0)R 0 ;
if(l > r - 1)R 0 ;
R query(0 , m - 1 , 1 , l , r - 1) ;
}
void solve(){
cin >> n >> m ;
for(ll i = 0 ; i < m ; i++){
cin >> o >> p >> a[i] ;
}
build(0 , m - 1 , 1 ) ;
ll kk ;
cin >> kk ;
while(kk--){
cin >> k ;
if(k == 1){
cin >> o >> p ;
update(0 , m - 1 , 1 , o - 1 , p) ;
}
else {
cin >> o >> p ;
ll l = 1 , r = o - 1;
ll o1 = o , o2 = o ;
while(l <= r){
if(op(mid , o) >= p)o1 = mid , r = mid - 1 ;
else l = mid + 1;
}
l = o + 1 , r = n ;
while(l <= r){
if(op(o , mid) >= p)o2 = mid , l = mid + 1 ;
else r = mid - 1 ;
}
cout << o2 - o1 + 1 << endl ;
}
}
}
int main(){
fast ;
//cin >> q;
q = 1;
while(q--){
solve();
}
}
