이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define pii pair<int, int>
#define pll pair<ll, ll>
#define ff first
#define ss second
#define pb push_back
#define SZ(x) ((int)(x).size())
#define all(x) x.begin(), x.end()
#define debug(x) cout << #x << ": " << x << " "
#define nl cout << "\n"
#define rep(i, a, b) for(int i = (a); i <= (b); i++)
#define per(i, a, b) for(int i = (a); i >= (b); i--)
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
long long find_shortcut(int N, vector<int> l, vector<int> p, int C){
    vector<ll> L(N), P(N);
    rep(i, 0, N - 1){
        if(i) L[i] = L[i - 1] + l[i - 1];
        P[i] = p[i];
    }
    auto dist = [&](int i, int j, int l, int r){
        ll ans = P[i] + P[j] + min({L[j] - L[i], C + abs(L[j] - L[r]) + abs(L[l] - L[i]), C + abs(L[j] - L[l])+ abs(L[r] - L[i])});
        return ans;
    };
    auto diameter = [&](int l, int r){
        ll ans = 0;
        rep(i, 0, N - 1){
            rep(j, i + 1, N - 1){
                ans = max(ans, dist(i, j, l, r));
            }
        }
        return ans;
    };
    ll ans = LLONG_MAX;
    rep(i, 0, N - 1){
        rep(j, i + 1, N - 1){
            ans = min(ans, diameter(i, j));
        }
    }
    return ans;
}
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