Submission #406840

#TimeUsernameProblemLanguageResultExecution timeMemory
406840cheissmartWiring (IOI17_wiring)C++14
100 / 100
61 ms8800 KiB
#include "wiring.h" #include <bits/stdc++.h> #define IO_OP std::ios::sync_with_stdio(0); std::cin.tie(0); #define F first #define S second #define V vector #define PB push_back #define MP make_pair #define EB emplace_back #define ALL(v) (v).begin(), (v).end() using namespace std; typedef long long ll; typedef pair<int, int> pi; typedef V<int> vi; string _reset = "\u001b[0m", _yellow = "\u001b[33m", _bold = "\u001b[1m"; void DBG() { cerr << "]" << _reset << endl; } template<class H, class...T> void DBG(H h, T ...t) { cerr << to_string(h); if(sizeof ...(t)) cerr << ", "; DBG(t...); } #ifdef CHEISSMART #define debug(...) cerr << _yellow << _bold << "Line(" << __LINE__ << ") -> [" << #__VA_ARGS__ << "]: [", DBG(__VA_ARGS__) #else #define debug(...) #endif const int INF = 1e9 + 7; const ll oo = 1e18; ll min_total_length(vi r, vi b) { V<pi> a; for(int i:r) a.EB(i, 0); for(int i:b) a.EB(i, 1); sort(ALL(a)); V<pi> seg; int n = a.size(); for(int i = 0; i < n; ) { int j = i; while(i < n && a[i].S == a[j].S) i++; seg.EB(j, i - 1); } V<ll> p(n); for(int i = 0; i < n; i++) p[i] = a[i].F + (i ? p[i - 1] : 0LL); auto ps = [&] (int l, int r) { return p[r] - (l ? p[l - 1] : 0LL); }; V<ll> dp(n + 1, oo); dp[n] = 0; assert(int(seg.size()) >= 2); debug(seg.size()); for(int i = int(seg.size()) - 2; i >= 0; i--) { int l1 = seg[i].F, r1 = seg[i].S, l2 = seg[i + 1].F, r2 = seg[i + 1].S; { // case 1: left size <= right size V<ll> aux(r2 - l2 + 3, oo); for(int j = r2; j >= l2; j--) { aux[j - l2 + 1] = min(dp[j + 1], dp[j]) + ps(l2, j) - (ll) (j - l2 + 1) * a[r1].F; aux[j - l2 + 1] = min(aux[j - l2 + 1], aux[j - l2 + 2]); } for(int j = 1; j <= min(r1 - l1 + 1, r2 - l2 + 1); j++) dp[r1 - j + 1] = min(dp[r1 - j + 1], aux[j] + (ll) j * a[r1].F - ps(r1 - j + 1, r1)); } { // case2: left size >= right size ll best = oo, lz = 0; for(int j = 1; j <= r1 - l1 + 1; j++) { lz += a[l2].F; if(l2 + j - 1 <= r2) best = min(best, min(dp[l2 + j], dp[l2 + j - 1]) + ps(l2, l2 + j - 1) - lz); dp[r1 - j + 1] = min(dp[r1 - j + 1], best + lz - ps(r1 - j + 1, r1)); } } debug(l1, r1, l2, r2); for(int i = l1; i <= r1; i++) debug(i, dp[i]); } return dp[0]; }
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