Submission #406138

#TimeUsernameProblemLanguageResultExecution timeMemory
406138zaneyuFrom Hacks to Snitches (BOI21_watchmen)C++14
5 / 100
1331 ms54728 KiB
/*input 6 6 1 2 2 3 3 4 4 5 5 2 5 6 1 4 4 5 2 3 */ #include<bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace std; using namespace __gnu_pbds; typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> indexed_set; //#pragma GCC optimize("O2","unroll-loops","no-stack-protector") //order_of_key #of elements less than x // find_by_order kth element using ll=long long; using ld=long double; using pii=pair<int,int>; #define f first #define s second #define pb push_back #define REP(i,n) for(int i=0;i<n;i++) #define REP1(i,n) for(int i=1;i<=n;i++) #define FILL(n,x) memset(n,x,sizeof(n)) #define ALL(_a) _a.begin(),_a.end() #define sz(x)(int)x.size() #define SORT_UNIQUE(c)(sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end())))) const ll INF64=4e18; const int INF=0x3f3f3f3f; const ll MOD=998244353; const ld PI=acos(-1); const ld eps=1e-9; #define lowb(x) x&(-x) #define MNTO(x,y) x=min(x,(__typeof__(x))y) #define MXTO(x,y) x=max(x,(__typeof__(x))y) inline ll mult(ll a,ll b){ if(a<0) a+=MOD; if(b<0) b+=MOD; if(a>=MOD) a%=MOD; if(b>=MOD) b%=MOD; return(a*b)%MOD; } inline ll mypow(ll a,ll b){ if(b<=0) return 1; ll res=1LL; while(b){ if(b&1) res=mult(res,a); a=mult(a,a); b>>=1; } return res; } const int maxn=15e6+5; int dist[maxn]; int arr[125]; vector<int> v[100005]; int main(){ ios::sync_with_stdio(false),cin.tie(0); int n,m; cin>>n>>m; REP(i,m){ int a,b; cin>>a>>b; --a; --b; v[a].pb(b); v[b].pb(a); } REP(i,n) dist[i]=INF; int k; cin>>k; int l; REP(i,k){ cin>>l; REP(j,l) cin>>arr[j],--arr[j]; } REP(i,n*l) dist[i]=INF; queue<int> q; q.push(0); dist[0]=0; while(!q.empty()){ int z=q.front(); q.pop(); int i=z%l,j=z/l; if(arr[(i+1)%l]!=j){ int asd=j*l+(i+1)%l; if(dist[asd]>dist[z]+1){ dist[asd]=dist[z]+1; q.push(asd); } } for(auto x:v[j]){ if(x!=arr[(i+1)%l] and !(j==arr[(i+1)%l] and x==arr[i%l])){ int asd=x*l+(i+1)%l; if(dist[asd]>dist[z]+1){ dist[asd]=dist[z]+1; q.push(asd); } } } } int ans=INF; REP(i,l) MNTO(ans,dist[(n-1)*l+i]); if(ans==INF) cout<<"impossible"; else cout<<ans; }
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