Submission #406106

#	Time	Username	Problem	Language	Result	Execution time	Memory
406106		zaneyu	From Hacks to Snitches (BOI21_watchmen)	C++14	0 / 100	99 ms	6160 KiB

watchmen

/*input
6 6
1 2
2 3
3 4
4 5
5 2
5 6
1
4 3 2 5 4
*/


#include<bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
typedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update> indexed_set;
//#pragma GCC optimize("O2","unroll-loops","no-stack-protector")
//order_of_key #of elements less than x
// find_by_order kth element
using ll=long long;
using ld=long double;
using pii=pair<int,int>;
#define f first
#define s second
#define pb push_back
#define REP(i,n) for(int i=0;i<n;i++)
#define REP1(i,n) for(int i=1;i<=n;i++)
#define FILL(n,x) memset(n,x,sizeof(n))
#define ALL(_a) _a.begin(),_a.end()
#define sz(x)(int)x.size()
#define SORT_UNIQUE(c)(sort(c.begin(),c.end()),c.resize(distance(c.begin(),unique(c.begin(),c.end()))))
const ll INF64=4e18;
const int INF=0x3f3f3f3f;
const ll MOD=998244353;
const ld PI=acos(-1);
const ld eps=1e-9;
#define lowb(x) x&(-x)
#define MNTO(x,y) x=min(x,(__typeof__(x))y)
#define MXTO(x,y) x=max(x,(__typeof__(x))y)
inline ll mult(ll a,ll b){
    if(a<0) a+=MOD;
    if(b<0) b+=MOD;
    if(a>=MOD) a%=MOD;
    if(b>=MOD) b%=MOD;
    return(a*b)%MOD;
}
inline ll mypow(ll a,ll b){
    if(b<=0) return 1;
    ll res=1LL;
    while(b){
        if(b&1) res=mult(res,a);
        a=mult(a,a);
        b>>=1;
    }
    return res;
}
const int maxn=1e5+5;
int dist[maxn];
int arr[maxn];
vector<int> v[maxn];
int main(){
    int n,m;
    cin>>n>>m;
    REP(i,m){
        int a,b;
        cin>>a>>b;
        --a;
        --b;
        v[a].pb(b);
        v[b].pb(a);
    }
    REP(i,n) dist[i]=INF;
    int k;
    cin>>k;
    int l;
    REP(i,k){
        cin>>l;
        REP(j,l) cin>>arr[j],--arr[j];
    }
    queue<int> q;
    q.push(0);
    dist[0]=0;
    while(!q.empty()){
        int z=q.front();
        q.pop();
        for(auto x:v[z]){
            int pv=dist[x];
            if(x!=arr[(dist[z]+1)%l] and !(x==arr[dist[z]%l] and z==arr[(dist[z]+1)%l])) MNTO(dist[x],dist[z]+1);
            else if(z!=(arr[(dist[z]+1)%l])) MNTO(dist[x],dist[z]+2);
            else MNTO(dist[x],dist[z]+3);
            if(pv!=dist[x]) q.push(x);
        }
    }
    //REP(i,n) cout<<dist[i]<<' ';
    if(dist[n-1]==INF) cout<<"impossible";
    else cout<<dist[n-1];

}

• Subtask 1: 0 / 5
• Subtask 2: 0 / 10
• Subtask 3: 0 / 10
• Subtask 4: 0 / 10
• Subtask 5: 0 / 25
• Subtask 6: 0 / 20
• Subtask 7: 0 / 20