# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
40589 | baactree | Treasure (different grader from official contest) (CEOI13_treasure2) | C++14 | 2 ms | 684 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "treasure.h"
#include <string.h>
#include <stdio.h>
int tree[105];
int col[105];
int mat[105][105];
int n, m;
bool flip;
int calc(int r1, int c1, int r2, int c2) {
int ret = 0;
if (r1 == 1) {
if (c2 - c1 + 1 > c1-1)
ret=countTreasure(r1, c1, n, n);
else
ret=m - countTreasure(1, 1, n, c1-1);
}
else {
ret=countTreasure(r1, c1, r2, c2);
}
if (flip)
ret = (r2 - r1 + 1)*(c2 - c1 + 1) - ret;
return ret;
}
void update(int idx, int val) {
idx = 105 - idx;
while (idx < 105) {
tree[idx] += val;
idx += idx&(-idx);
}
}
int query(int idx) {
int ret = 0;
idx = 105 - idx;
while (idx) {
ret += tree[idx];
idx -= idx&(-idx);
}
return ret;
}
void solve_col(int le, int ri, int cnt) {
if (!cnt)
return;
if (le == ri) {
col[le] = cnt;
update(le, cnt);
return;
}
int mid = (le + ri) / 2;
int right = calc(1, mid + 1, n, n) - query(ri);
int left = cnt - right;
solve_col(mid + 1, ri, right);
solve_col(le, mid, left);
}
void solve_row(int le, int ri, int cnt,int col) {
if (!cnt)
return;
if (le == ri) {
mat[le][col] = 1;
update(le, cnt);
return;
}
int mid = (le + ri) / 2;
int right = calc(mid + 1, col, n, n) - query(ri);
int left = cnt - right;
solve_row(mid + 1, ri, right, col);
solve_row(le, mid, left, col);
}
void findTreasure (int N) {
memset(tree, 0, sizeof(tree));
memset(mat, 0, sizeof(mat));
memset(col, 0, sizeof(col));
n = N;
m = countTreasure(1, 1, n, n);
if (m > n*n / 2)
flip = true;
solve_col(1, n, n*n-m);
memset(tree, 0, sizeof(tree));
for (int i = n; i >= 1; i--)
solve_row(1, n, col[i],i);
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++) {
if (flip && !mat[i][j])
Report(i, j);
if(!flip&&mat[i][j])
Report(i, j);
}
}
Compilation message (stderr)
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