Submission #404234

#TimeUsernameProblemLanguageResultExecution timeMemory
404234timmyfengSkyscraper (JOI16_skyscraper)C++17
100 / 100
140 ms120316 KiB
#include <bits/stdc++.h> using namespace std; const int N = 101, L = 1001, M = 1000000007; struct mint { int x; mint() : x(0) {} template <class T> mint(T value) : x(value % M) { if (x < 0) x += M; } mint & operator+=(const mint &oth) { x += oth.x; if (x >= M) x -= M; return *this; } mint & operator-=(const mint &oth) { x -= oth.x; if (x < 0) x += M; return *this; } mint & operator*=(const mint &oth) { x = (long long) x * oth.x % M; return *this; } friend mint operator+(mint l, const mint &r) { return l += r; } friend mint operator-(mint l, const mint &r) { return l -= r; } friend mint operator*(mint l, const mint &r) { return l *= r; } mint & operator--() { if (--x == -1) x = M - 1; return *this; } mint & operator++() { if (++x == M) x = 0; return *this; } mint operator--(int) { mint temp = *this; --*this; return temp; } mint operator++(int) { mint temp = *this; ++*this; return temp; } mint operator-() const { return 0 - *this; } mint operator+() const { return *this; } friend bool operator==(const mint &l, const mint &r) { return l.x == r.x; } friend bool operator!=(const mint &l, const mint &r) { return l.x != r.x; } friend ostream & operator<<(ostream &out, const mint &a) { return out << a.x; } mint pow(long long e = M - 2) const { mint ans = 1, b = *this; while (e > 0) { if (e % 2 == 1) { ans *= b; } b *= b; e /= 2; } return ans; } }; mint ways[N][N][L][3]; int a[N]; int main() { ios_base::sync_with_stdio(false); cin.tie(nullptr); int n, l; cin >> n >> l; for (int i = 0; i < n; ++i) { cin >> a[i]; } sort(a, a + n); if (n == 1) { cout << 1 << "\n"; exit(0); } ways[0][0][0][0] = 1; for (int i = 0; i < n; ++i) { for (int j = 0; j <= i; ++j) { for (int k = 0; k <= l; ++k) { for (int p = 0; p <= 2; ++p) { int k_new = k + (2 * j - p) * (i > 0 ? a[i] - a[i - 1] : 0); if (k_new > l || ways[i][j][k][p] == 0) { continue; } if (j >= 2) { ways[i + 1][j - 1][k_new][p] += (j - 1) * ways[i][j][k][p]; } if (j >= 1) { ways[i + 1][j][k_new][p] += (2 * j - p) * ways[i][j][k][p]; if (p < 2) { ways[i + 1][j][k_new][p + 1] += (2 - p) * ways[i][j][k][p]; } } ways[i + 1][j + 1][k_new][p] += (j + 1 - p) * ways[i][j][k][p]; if (p < 2) { ways[i + 1][j + 1][k_new][p + 1] += (2 - p) * ways[i][j][k][p]; } } } } } mint ans = 0; for (int i = 0; i <= l; ++i) { ans += ways[n][1][i][2]; } cout << ans << "\n"; }
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