# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|
403591 | | lyc | 족보 (KOI18_family) | C++14 | | 3069 ms | 47820 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <bits/stdc++.h>
using namespace std;
#define TRACE(x) cerr << #x << " :: " << x << endl
#define _ << " " <<
#define SZ(x) (int)(x).size()
#define ALL(x) (x).begin(),(x).end()
#define FOR(i,a,b) for(int i=(a);i<=(b);++i)
#define RFOR(i,a,b) for (int i=(a);i>=(b);--i)
const int mxN = 3e5+5;
const int mxK = 3e5+5;
const int inf = 1e9+5;
int K;
struct Tree {
int N;
vector<int> g[mxN];
int pa[mxN][14];
int dep[mxN];
void read() {
FOR(i,1,N){
int P; cin >> P;
g[P].push_back(i);
}
}
void dfs(int u) {
FOR(k,1,13) pa[u][k] = (pa[u][k-1] == -1 ? -1 : pa[pa[u][k-1]][k-1]);
for (int& v : g[u]) {
pa[v][0] = u;
dep[v] = dep[u]+1;
dfs(v);
}
}
int lca(int a, int b) {
if (dep[a] < dep[b]) swap(a,b);
RFOR(k,13,0) if (pa[a][k] != -1 && dep[pa[a][k]] >= dep[b]) {
a = pa[a][k];
}
if (a == b) return a;
RFOR(k,13,0) if (pa[a][k] != pa[b][k]) {
a = pa[a][k], b = pa[b][k];
}
return pa[a][0];
}
void run() {
memset(pa,-1,sizeof pa);
dep[0] = 0;
dfs(0);
}
inline int lcd(int a, int b) {
return dep[lca(a,b)];
}
} A, B;
struct node {
int s, e, m, v;
node *l, *r;
node (int s, int e): s(s), e(e), m((s+e)/2), v(inf) {
if (s != e) {
l = new node(s,m);
r = new node(m+1,e);
}
}
void update(int a, int b) {
if (s == e) { v = min(v,b); return; }
if (a <= m) l->update(a,b);
else r->update(a,b);
v = min(l->v,r->v);
}
int qmin(int a, int b) {
if (s == a && e == b) return v;
if (b <= m) return l->qmin(a,b);
if (a > m) return r->qmin(a,b);
return min(l->qmin(a,m), r->qmin(m+1,b));
}
void reset() {
v = inf;
if (s == e) return;
l->reset();
r->reset();
}
} *root;
int main() {
ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);
cin >> A.N >> B.N >> K;
A.read();
B.read();
A.run();
B.run();
bool die = 0;
root = new node(1,A.N);
FOR(i,1,K){
root->reset();
FOR(j,1,K) if (j != i) {
int a = A.lcd(i,j), b = B.lcd(i,j);
root->update(a,b);
}
FOR(j,1,K) if (j != i) {
int a = A.lcd(i,j), b = B.lcd(i,j);
if (a < A.N) die |= b > root->qmin(a+1,A.N);
}
}
cout << (die ? "NO" : "YES") << '\n';
}
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