# | Time | Username | Problem | Language | Result | Execution time | Memory |
---|---|---|---|---|---|---|---|
403412 | shenxy | 조개 줍기 (KOI17_shell) | C++11 | 628 ms | 26464 KiB |
This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include <cstdio>
#include <algorithm>
#include <queue>
using namespace std;
typedef pair<int, int> ii;
int main() {
int N;
scanf("%d", &N);
if (N <= 100) {
int A[N][N], S[N][N];
for (int i = 0; i < N; ++i) {
for (int j = 0; j < N; ++j) scanf("%d", &A[i][j]);
}
int r, c, ans = 0;
char op;
S[0][0] = A[0][0];
for (int i = 1; i < N; ++i) S[i][0] = S[i - 1][0] + A[i][0], S[0][i] = S[0][i - 1] + A[0][i];
for (int i = 1; i < N; ++i) {
for (int j = 1; j < N; ++j) S[i][j] = max(S[i - 1][j], S[i][j - 1]) + A[i][j];
}
for (int i = 0; i < N; ++i) {
for (int j = 0; j < N; ++j) ans += S[i][j];
}
printf("%d\n", ans);
for (int i = 0; i < N; ++i) {
scanf(" %c %d %d", &op, &r, &c);
if (op == 'U') ++A[r - 1][c - 1];
else --A[r - 1][c - 1];
S[0][0] = A[0][0];
ans = 0;
for (int i = 1; i < N; ++i) S[i][0] = S[i - 1][0] + A[i][0], S[0][i] = S[0][i - 1] + A[0][i];
for (int i = 1; i < N; ++i) {
for (int j = 1; j < N; ++j) S[i][j] = max(S[i - 1][j], S[i][j - 1]) + A[i][j];
}
for (int i = 0; i < N; ++i) {
for (int j = 0; j < N; ++j) ans += S[i][j];
}
printf("%d\n", ans);
}
} else {
int A[N + 1][N + 1], S[N + 1][N + 1];
for (int i = 1; i <= N; ++i) {
for (int j = 1; j <= N; ++j) scanf("%d", &A[i][j]);
}
int r[N], c[N], ans[N + 1];
char op;
for (int i = 0; i < N; ++i) scanf(" %c %d %d", &op, &r[i], &c[i]), --A[r[i]][c[i]];
for (int i = 0; i <= N; ++i) S[0][i] = S[i][0] = 0;
for (int i = 1; i <= N; ++i) {
for (int j = 1; j <= N; ++j) S[i][j] = max(S[i - 1][j], S[i][j - 1]) + A[i][j];
}
ans[N] = 0;
for (int i = 1; i <= N; ++i) {
for (int j = 1; j <= N; ++j) ans[N] += S[i][j];
}
for (int i = N - 1; i >= 0; --i) {
++A[r[i]][c[i]];
queue<ii> pq;
pq.push(ii(r[i], c[i]));
ans[i] = ans[i + 1] + 1;
++S[r[i]][c[i]];
while (!pq.empty()) {
int j = pq.front().first, k = pq.front().second;
pq.pop();
if (j != N && S[j + 1][k] != max(S[j][k], S[j + 1][k - 1]) + A[j + 1][k]) {
S[j + 1][k] = max(S[j][k], S[j + 1][k - 1]) + A[j + 1][k];
++ans[i];
pq.push(ii(j + 1, k));
}
if (k != N && S[j][k + 1] != max(S[j - 1][k + 1], S[j][k]) + A[j][k + 1]) {
S[j][k + 1] = max(S[j - 1][k + 1], S[j][k]) + A[j][k + 1];
++ans[i];
pq.push(ii(j, k + 1));
}
}
}
for (int i = 0; i <= N; ++i) printf("%d\n", ans[i]);
}
return 0;
}
Compilation message (stderr)
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