제출 #401272

#제출 시각아이디문제언어결과실행 시간메모리
401272amunduzbaevTravelling Merchant (APIO17_merchant)C++14
100 / 100
139 ms4188 KiB
/* made by amunduzbaev */ #include <bits/stdc++.h> //#include <ext/pb_ds/assoc_container.hpp> //#include <ext/pb_ds/tree_policy.hpp> using namespace std; //using namespace __gnu_pbds; #define ff first #define vv vector #define ss second #define pb push_back #define mp make_pair #define ub upper_bound #define lb lower_bound #define sz(x) (int)x.size() #define tut(x) array<int, x> #define all(x) x.begin(), x.end() #define rall(x) x.rbegin(),x.rend() #define NeedForSpeed ios::sync_with_stdio(0);cin.tie(0);cout.tie(0); #define int long long typedef long long ll; typedef long double ld; typedef pair<int, int> pii; typedef vector<int> vii; typedef vector<pii> vpii; template<class T> bool umin(T& a, const T& b) { return a > b? a = b, true:false; } template<class T> bool umax(T& a, const T& b) { return a < b? a = b, true:false; } //void usaco(string s) { freopen((s+".in").c_str(),"r",stdin); //freopen((s+".out").c_str(),"w",stdout); } //template<class T> tree<T, //less<T>, null_type, rb_tree_tag, //tree_order_statistics_node_update> ordered_set; const int N = 105; const int mod = 1e9+7; const ll inf = 1e16; const ld Pi = acos(-1); #define MULTI 0 int n, m, k, ans, q, res, a[N]; int b[N][1005], s[N][1005]; int tt[N][N], prof[N][N]; int mx[N][N]; bool check(int m){ for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ mx[i][j] = -inf; if(tt[i][j] == inf || i == j) continue; mx[i][j] = prof[i][j] - m * tt[i][j]; } } for(int k=1;k<=n;k++){ for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ umax(mx[i][j], mx[i][k] + mx[k][j]); } } } for(int i=1;i<=n;i++) if(mx[i][i] >= 0) return 1; return 0; } void solve(int t_case){ cin>>n>>m>>k; for(int i=1;i<=n;i++){ for(int j=0;j<k;j++){ cin>>b[i][j]>>s[i][j]; } } for(int i=1;i<=n;i++) for(int j=1;j<=n;j++) tt[i][j] = inf; for(int i=0;i<m;i++){ int a, b, c; cin>>a>>b>>c; umin(tt[a][b], c); } int K = k; for(int k=1;k<=n;k++){ for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ umin(tt[i][j], tt[i][k] + tt[k][j]); } for(int j=0;j<K;j++){ if(~b[i][j] && ~s[k][j]) umax(prof[i][k], - b[i][j] + s[k][j]); } } } int l = 0, r = mod; while(l < r){ int m = (l + r + 1)>>1; if(check(m)) l = m; else r = m-1; } cout<<l<<"\n"; } signed main(){ NeedForSpeed if(!MULTI) { solve(1); } else { int t; cin>>t; for(int t_case = 1; t_case <= t; t_case++) solve(t_case); } return 0; }
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