Submission #400362

#	Time	Username	Problem	Language	Result	Execution time	Memory
400362		abdzag	Cloud Computing (CEOI18_clo)	C++17	100 / 100	2226 ms	5316 KiB

clo

#include<bits/stdc++.h>
#include<unordered_map>
#define rep(i,a,b) for(int i=int(a);i<int(b);i++)
#define rrep(i,a,b) for(int i=int(a);i>int(b);i--)
#define all(v) v.begin(),v.end()
#define trav(a,v) for(auto&a:v)
#define  sz(a) a.size()
typedef long double ld;
using namespace std;
const long long inf = 1e15;
typedef long long ll;
typedef unsigned long long ull;

int main()
{
    cin.sync_with_stdio(false);
    ll n,m;
    cin >> n;
    vector<pair<pair<ll, ll>, pair<ll, ll>>> v(n);
    rep(i, 0, n) {
        cin >> v[i].second.first >> v[i].first.first >> v[i].second.second;
        v[i].first.first *= -1;
    }
    cin >> m;
    v.resize(n + m);
    rep(i, n, n+m) {
        cin >> v[i].second.first >> v[i].first.first >> v[i].second.second;
        v[i].first.first *= -1;
        v[i].first.second = 1;
    }
    sort(all(v));
    vector<ll>dp(3e5, -inf);
    dp[0] = 0;
    vector<ll> dp0 = dp;
    ll sumc = 1;
    rep(i, 0, n+m) {
        rep(j, 0, 2e5) {
            if (!v[i].first.second) {
                if (dp0[j] != -inf)if(v[i].second.first + j<dp.size())dp[v[i].second.first + j] = max(dp0[v[i].second.first + j], dp0[j]-v[i].second.second);
            }
            else {
                if (dp0[j] != -inf)if (-v[i].second.first + j >= 0)dp[-v[i].second.first + j] = max(dp0[-v[i].second.first + j], dp0[j] + v[i].second.second);

            }
        }
        sumc += v[i].second.first;
        dp0 = dp;
    }
    ll ans = 0;
    rep(i, 0, 3e5)ans = max(dp[i], ans);
    cout<<ans;
    return 0;
}

Compilation message (stderr)

clo.cpp: In function 'int main()':
clo.cpp:39:60: warning: comparison of integer expressions of different signedness: 'long long int' and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   39 |                 if (dp0[j] != -inf)if(v[i].second.first + j<dp.size())dp[v[i].second.first + j] = max(dp0[v[i].second.first + j], dp0[j]-v[i].second.second);

• Subtask 1: 18 / 18
• Subtask 2: 18 / 18
• Subtask 3: 18 / 18
• Subtask 4: 18 / 18
• Subtask 5: 18 / 18
• Subtask 6: 10 / 10