제출 #399949

#제출 시각아이디문제언어결과실행 시간메모리
399949arwaeystoamnegSynchronization (JOI13_synchronization)C++17
100 / 100
1218 ms32088 KiB
// EXPLOSION! #define _CRT_SECURE_NO_WARNINGS #include<bits/stdc++.h> #include<unordered_set> #include<unordered_map> #include<chrono> using namespace std; typedef pair<int, int> pii; typedef long long ll; typedef pair<ll, ll> pll; typedef long double ld; typedef vector<int> vi; typedef vector<ll> vll; typedef vector<pair<int, int>> vpi; typedef vector<pair<ll, ll>> vpll; #define FOR(i,a,b) for (int i = (a); i < (b); ++i) #define F0R(i,a) FOR(i,0,a) #define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i) #define R0F(i,a) ROF(i,0,a) #define trav(a,x) for (auto& a: x) #define pb push_back #define mp make_pair #define rsz resize #define sz(x) int(x.size()) #define all(x) x.begin(),x.end() #define f first #define s second #define cont continue #define endl '\n' //#define ednl '\n' #define test int testc;cin>>testc;while(testc--) #define pr(a, b) trav(x,a)cerr << x << b; cerr << endl; #define message cout << "Hello World" << endl; const int dx[4] = { 1,0,-1,0 }, dy[4] = { 0,1,0,-1 }; // for every grid problem!! const ll linf = 4000000000000000000LL; const ll inf = 998244353;//998244353 1000000007 void pv(vi a) { trav(x, a)cout << x << " "; cout << endl; }void pv(vll a) { trav(x, a)cout << x << " "; cout << endl; }void pv(vector<vi>a) { F0R(i, sz(a)) { cout << i << endl; pv(a[i]); cout << endl; } }void pv(vector<vll>a) { F0R(i, sz(a)) { cout << i << endl; pv(a[i]); }cout << endl; }void pv(vector<string>a) { trav(x, a)cout << x << endl; cout << endl; } void setIO(string s) { ios_base::sync_with_stdio(0); cin.tie(0); #ifdef arwaeystoamneg if (sz(s)) { freopen((s + ".in").c_str(), "r", stdin); if (s != "test1") freopen((s + ".out").c_str(), "w", stdout); } #endif } template<class T>class segment_tree { struct item { T sum; }; item single(T i) { return { i }; } item merge(item x, item y) { item ans; ans.sum = x.sum + y.sum; return ans; } vector<item> tree; vector<item>A; int height; item neutral = { 0 }; public:void build(vector<T>& B) { int n = B.size(); height = log2(n + 1) + 1; A.rsz(n); tree.rsz((1 << height + 1) - 1); F0R(i, n)A[i] = single(B[i]); A.rsz(1 << height, neutral); build(A, 0, 0, (1 << height) - 1); } void build(vector<item>& A, int v, int tl, int tr) { if (tl == tr) tree[v] = A[tl]; else { int mid = (tl + tr) / 2; build(A, 2 * v + 1, tl, mid); build(A, 2 * v + 2, mid + 1, tr); tree[v] = merge(tree[2 * v + 1], tree[2 * v + 2]); } } public:T query(int l, int r) { return query(0, 0, (1 << height) - 1, l, r).sum; } item query(int v, int tl, int tr, int l, int r) { if (r<tl || l>tr)return neutral; if (l <= tl && r >= tr) { return tree[v]; } int mid = (tl + tr) / 2; return merge(query(2 * v + 1, tl, mid, l, r), query(2 * v + 2, mid + 1, tr, l, r)); } //assign public:void update(int pos, T val) { update(0, 0, (1 << height) - 1, pos, single(val)); } void update(int v, int tl, int tr, int pos, item val) { if (tl == tr) { tree[v] = merge(tree[v], val); } else { int mid = (tl + tr) / 2; if (pos <= mid) update(2 * v + 1, tl, mid, pos, val); else update(2 * v + 2, mid + 1, tr, pos, val); tree[v] = merge(tree[2 * v + 1], tree[2 * v + 2]); } } }; struct e { int x, y; int ans; bool a; int get(int z) { return x + y - z; } }; const int MAX = 100005, SZ = 20; e edge[MAX]; int n, m, q, tin[MAX], order[MAX], sizes[MAX], ptr, parent[MAX], ans[MAX], jump[SZ][MAX]; vi adj[MAX]; segment_tree<ll>sum; void dfs(int i, int p = -1) { sizes[i] = 1; parent[i] = p; tin[i] = ptr; order[ptr++] = i; trav(x, adj[i]) { int j = edge[x].get(i); if (j == p)continue; dfs(j, i); sizes[i] += sizes[j]; } } int get(int i, ll c) { R0F(j, SZ) { int k = jump[j][i]; if (k == -1)continue; if (sum.query(0, tin[k]) == c)i = k; } return i; } int main() { setIO("test1"); cin >> n >> m >> q; F0R(i, n - 1) { int x, y; cin >> x >> y; edge[i] = { --x,--y,0,0 }; adj[x].pb(i); adj[y].pb(i); } vll temp(n + 1, 1); sum.build(temp); dfs(0); F0R(i, n - 1)if (parent[edge[i].x] == edge[i].y)swap(edge[i].x, edge[i].y); fill(ans, ans + n, 1); F0R(i, n)jump[0][i] = parent[i]; F0R(i, SZ - 1) { F0R(j, n) { jump[i + 1][j] = (jump[i][j] == -1 ? -1 : jump[i][jump[i][j]]); } } ll cur = inf; while (m--) { int i; cin >> i; i--; if (edge[i].a == 0) { ll c = sum.query(0, tin[edge[i].x]); int j = get(edge[i].x, c); ans[j] += ans[edge[i].y] - edge[i].ans; ll d = sum.query(0, tin[j]) - sum.query(0, tin[edge[i].y]); sum.update(tin[edge[i].y], d); sum.update(tin[edge[i].y] + sizes[edge[i].y], -d); } else { ll c = sum.query(0, tin[edge[i].x]); int j = get(edge[i].x, c); edge[i].ans = ans[j]; ans[edge[i].y] = ans[j]; sum.update(tin[edge[i].y], cur); sum.update(tin[edge[i].y] + sizes[edge[i].y], -cur); cur += inf; } edge[i].a ^= 1; } while (q--) { int i; cin >> i; i--; ll c = sum.query(0, tin[i]); int j = get(i, c); cout << ans[j] << endl; } }

컴파일 시 표준 에러 (stderr) 메시지

synchronization.cpp: In instantiation of 'void segment_tree<T>::build(std::vector<_Tp>&) [with T = long long int]':
synchronization.cpp:186:16:   required from here
synchronization.cpp:80:24: warning: suggest parentheses around '+' inside '<<' [-Wparentheses]
   80 |  tree.rsz((1 << height + 1) - 1);
      |                 ~~~~~~~^~~
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