Submission #399634

#	Time	Username	Problem	Language	Result	Execution time	Memory
399634		Jarif_Rahman	Werewolf (IOI18_werewolf)	C++17	7 / 100	4080 ms	165496 KiB

werewolf

#include "werewolf.h"
#include <bits/stdc++.h>
#define pb push_back
#define f first
#define sc second
using namespace std;
typedef long long int ll;
typedef string str;

struct reachability_tree{
    int n;
    vector<int> p;
    vector<vector<int>> v;
    vector<int> w;
    reachability_tree(int _n, int _w){
        n = _n;
        p.resize(n);
        v.resize(n);
        w.resize(n, _w);
        for(int i = 0; i < n; i++) p[i] = i;
    }
    int get(int x){
        if(p[x] != x) p[x] = get(p[x]);
        return p[x];
    }
    void unite(int a, int b, int _w){
        a = get(a), b = get(b);
        p[a] = n, p[b] = n;
        p.pb(n);
        v.pb({});
        v[n].pb(a);
        if(a != b) v[n].pb(b);
        w.pb(_w);
        n++;
    }
};

int n, m, q;

reachability_tree rtl(0, 0), rtr(0, 0);

vector<int> szl, szr, al, ar, posl, posr;
vector<vector<int>> ancl, ancr;

void dfsl(int nd, int ss){
    posl[nd] = al.size();
    al.pb(nd);
    for(int x: rtl.v[nd]) if(x != ss) dfsl(x, nd);
    for(int x: rtl.v[nd]) szl[nd]+=szl[x];
    ancl[nd][1] = ss;
}
void dfsr(int nd, int ss){
    posr[nd] = ar.size();
    ar.pb(nd);
    for(int x: rtr.v[nd]) if(x != ss) dfsr(x, nd);
    for(int x: rtr.v[nd]) szr[nd]+=szr[x];
    ancr[nd][1] = ss;
}

int get_anc_l(int nd, int ss){
    for(int i = 1; i < 21; i++){
        if(ss%2 == 1) nd = ancl[nd][i];
        if(nd == -1) return -1;
        ss/=2;
    }
    return nd;
}
int get_anc_r(int nd, int ss){
    for(int i = 1; i < 21; i++){
        if(ss%2 == 1) nd = ancr[nd][i];
        if(nd == -1) return -1;
        ss/=2;
    }
    return nd;
}

int bsl(int nd, int vl){
    int a = 0, b = 8e5;
    while(a < b){
        int md = (a+b+1)/2;
        int x = get_anc_l(nd, md);
        if(x == -1) x = 1e9;
        else x = rtl.w[x];
        if(x > vl) b = md-1;
        else a = md;
    }
    return get_anc_l(nd, a);
}
int bsr(int nd, int vl){
    int a = 0, b = 8e5;
    while(a < b){
        int md = (a+b+1)/2;
        int x  = get_anc_r(nd, md);
        if(x == -1) x = -1;
        else x = rtr.w[x];
        if(x < vl) b = md-1;
        else a = md;
    }
    return get_anc_r(nd, a);
}

vector<int> check_validity(int n, vector<int> U, vector<int> V, vector<int> ss, vector<int> ee, vector<int> L, vector<int> R){
    ::n = n, m = U.size(), q = ss.size();
    vector<pair<int, int>> edgel(m), edger(m);
    for(int i = 0; i < m; i++)  edgel[i] = {U[i], V[i]}, edger[i] = {U[i], V[i]};

    sort(edgel.begin(), edgel.end(), [&](pair<int, int> a, pair<int, int> b){
        return max(a.f, a.sc) < max(b.f, b.sc);
    });
    sort(edger.begin(), edger.end(), [&](pair<int, int> a, pair<int, int> b){
        return min(a.f, a.sc) > min(b.f, b.sc);
    });

    rtl = reachability_tree(n, 0), rtr = reachability_tree(n, n+1);
    for(int i = 0; i < m; i++) rtl.unite(edgel[i].f, edgel[i].sc, max(edgel[i].f, edgel[i].sc)), rtr.unite(edger[i].f, edger[i].sc, min(edger[i].f, edger[i].sc));
    ancl.resize(rtl.n, vector<int>(21, -1));
    ancr.resize(rtr.n, vector<int>(21, -1));
    szl.resize(rtl.n, 1);
    szr.resize(rtr.n, 1);
    posl.resize(rtl.n);
    posr.resize(rtr.n);
    dfsl(rtl.n-1, -1);
    dfsr(rtr.n-1, -1);

    for(int i = 0; i < rtl.n; i++) ancl[i][0] = i;
    for(int i = 0; i < rtr.n; i++) ancr[i][0] = i;
    for(int i = 2; i < 21; i++) for(int j = 0; j < rtl.n; j++){
        if(ancl[j][i-1] == -1) continue;
        ancl[j][i] = ancl[ancl[j][i-1]][i-1];
    }
    for(int i = 2; i < 21; i++) for(int j = 0; j < rtr.n; j++){
        if(ancr[j][i-1] == -1) continue;
        ancr[j][i] = ancr[ancr[j][i-1]][i-1];
    }

    vector<int> ans(q);
    for(int qq = 0; qq < q; qq++){
        int ndl = bsl(ee[qq], R[qq]), ndr = bsr(ss[qq], L[qq]);
        cerr << ndl << " " << ndr << " d\n";
        for(int i = posl[ndl]; i < posl[ndl]+szl[ndl]; i++) for(int j = posr[ndr]; j < posr[ndr]+szr[ndr]; j++) if(al[i] == ar[j] && al[i] < n) ans[qq] = 1;
    }

    return ans;
}

• Subtask 1: 7 / 7
• Subtask 2: 0 / 8
• Subtask 3: 0 / 34
• Subtask 4: 0 / 51